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mihalych1998 [28]
3 years ago
5

At what point in a projectile’s trajectory does it experience a minimum velocity? as soon as it is launched half way to its high

est point at its highest point just before it lands
Physics
2 answers:
andrew-mc [135]3 years ago
6 0

Answer:

at the highest point

Explanation:

velocity of a particle becomes minimum when the  particle projected halfway or from ground reaches its maximum height.

VLD [36.1K]3 years ago
5 0
No matter what direction a projectile is traveling, its velocity
will be minimum at the highest point in its trajectory.

I just realized ... that's also true of an Earth satellite.
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A 50 n force is acting on a lever 1.5 m from the fulcrum balances an object 1m from the fulcrum on the other arm. what is the we
Angelina_Jolie [31]

Answer:

A 100 N force acting on a lever 2 m from the fulcrum balances an object 0.5 m from the fulcrum on. ... What is the weight of the object(in newtons)? What is its mass (in kg)? ... mass at the one end and effort arm is the distance between pivot and effort applied at the other end.

Explanation:

hpoe this helps you.

4 0
3 years ago
13. in batesian mimicry, a palatable species gains protection by mimicking an unpalatable one. imagine that individuals of a pal
fiasKO [112]

Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

<h3>What is Batesian mimicry?</h3>

Batesian mimicry can be defined as a type of adaptive feature associated with the coloration of a particular species and/or population.

On the first island, the color of the population won't change because of the absence of predators.

On the second island, the color of the population will change because of the presence of predators that can be alerted by the color.

On the third island, the color of the population won't change because of the presence of a species with a similar color.

In conclusion, Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

Learn more about Batesian mimicry here:

brainly.com/question/14139071

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6 0
2 years ago
WILL GIVE THE BRAINLIEST!!!
True [87]

Answer:

E

Explanation:

The police car is going to fast for the cop to hear and the same is with the speeder its who hears its highest pitch because it drives right past you and your not moving just standing on the cross walk

6 0
3 years ago
Read 2 more answers
Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge of Object 2 is tripled, then the new
Leya [2.2K]

Answer:

The force will be 54.0 units

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

F=\frac{kq_1 q_2}{r^2}

where

k is Coulomb's constant

q1, q2 are the magnitude of the two charges

r is the separation between the two charges

From the equation, we see that the magnitude of the force is directly proportional to the charge of object 2:

F\propto q_2

In this problem, the initial force between the two objects is

F = 18.0 N

And so, when the charge on object 2 is tripled,

q_2'=3q_2

The new electrostatic force will be

F'\propto q_2' = (3q_2) = 3F

So, the force will also triple: since the original force was 18.0 units, the new force will be

F'=3F=3(18.0)=54.0

5 0
3 years ago
A capacitor with an initial potential difference of 185 V is discharged through a resistor when a switch between them is closed
GrogVix [38]

Answer:

  • a. \tau =  2.1161 s
  • b. V(18.8 \ s) = 0.0256 \ V

Explanation:

<h3>a.</h3>

The equation for the voltage V of  discharging capacitor in an RC circuit at time t is:

V(t) = V_0 e^{(- \frac{t}{\tau}) }

where V_0 is the initial voltage, and \tau is the time constant.

For our problem, we know

V_0 = 185 \ V

and

V(10 \ s) = V_0 e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V

So

185 \ V \ e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V

e^{(- \frac{10 \ s}{\tau}) } = \frac{1.64 \ V}{ 185 \ V }

ln (e^{(- \frac{10 \ s}{\tau}) } ) = ln (\frac{1.64 \ V}{ 185 \ V })

- \frac{10 \ s}{\tau}  = ln (\frac{1.64 \ V}{ 185 \ V })

\tau =  \frac{-10 \s}{ln (\frac{1.64 \ V}{ 185 \ V }) }

This gives us

\tau =  2.1161 s

and this is the time constant.

<h3>b.</h3>

At t = 18.8 s we got:

V(18.8 \ s) = 185 \ V  \ e^{(- \frac{18.8 \ s}{2.1161 s}) }

V(18.8 \ s) = 185 \ V \ e^{(- \frac{18.8 \ s}{2.1161 s}) }

V(18.8 \ s) = 0.0256 \ V

4 0
3 years ago
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