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3 years ago

Is there more forms of energy of there than :

Physics

1 answer:

bogdanovich [222]3 years ago

7 0

Motion of things cause the energy such as the nuclear and the chemicals around temperature traveles

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How fast must a 70 kg student be running to have a kinetic energy of 568 J?!

Dmitry [639]

Answer: 4.03 m/s

Explanation: Kinetic energy is

KE = 1/2 m v²

So we derive the equation to have v.

v = √ 2KE / m

= 2 x 568 J / 70 kg

= 16.23

= √ 16.23

= 4.03 m/s

4 0

3 years ago

A roller-coaster track has six semicircular "dips" with different radii of curvature. The same roller-coaster cart rides through

inessss [21]

Answer:

E > A = B > C > D

Explanation:

On a semicircular curve, the magnitude of force is given by the formula as :

$F=\dfrac{mv^2}{r}$

Here, m is the mass of the vehicle

Case A : R = 60 m v = 16 m/s

$F_1=\dfrac{m(16)^2}{60}=4.27m\ N$

Case B : R = 15 m v = 8 m/s

$F_2=\dfrac{m(8)^2}{15}=4.27m\ N$

Case C : R = 30 m v = 4 m/s

$F_3=\dfrac{m(4)^2}{30}=0.534m\ N$

Case D : R = 45 m v = 4 m/s

$F_4=\dfrac{m(4)^2}{45}=0.356m\ N$

Case E : R = 30 m v = 16 m/s

$F_5=\dfrac{m(16)^2}{30}=8.53m\ N$

The order of the magnitude of the force of the roller-coaster track on the cart from largest to smallest is :

E > A = B > C > D

6 0

3 years ago

You are working at a company that manufactures electrical wire. Gold is the most ductile of all metals: it can be stretched into

devlian [24]

Answer: $R=1.424 M\Omega$

Explanation:

Given

mass of gold $m=1.6 gm$

Length of wire $L=2.2 km$

Resistivity of gold $\rho =2.44\times 10^{-8}$

density of gold $=19.3\times 10^3 kg/m^3$

and $mass=volume\times density$

$1.6\times 10^{-3}=volume\times 19.3\times 10^3$

$volume=8.29\times 10^{-8} m^3$

And $Resistance R=\frac{\rho L}{A}$

also be written as

$R=\frac{\rho L^2}{V}$

where $L=length$

$V=volume$

$\rho =resistivity\ of\ gold$

$R=\frac{2.44\times 10^{-8}\times (2200)^2}{8.29 \times 10^{-8}}$

$R=1.42\times 10^{6} \Omega$

$R=1.424 M\Omega$

5 0

3 years ago

A gun can fire a bullet at 540 m/s. If the gun is aimed at an angle of 55o above the horizontal and fired, what will be the hori

lisabon 2012 [21]

Answer:

Explanation:

The <u>initial</u> vertical velocity is 540sin55° = 442.342103... 442 m/s

The <u>initial</u> horizontal velocity is 540cos55° = 309.731275... 310 m/s

In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.

5 0

3 years ago

Assume this field is generated by a point charge of Q = 5 × 10-9 C. How far away is this charge located? Give your answer in met

marshall27 [118]

E=Eq,

where F is the electrostatic force (or Coulomb force) exerted on a positive test charge q.

7 0

3 years ago