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Zinaida [17]
2 years ago
13

A 13.00 g sample of citric acid reacts with an excess of baking soda as shown in the equation.

Chemistry
1 answer:
Shtirlitz [24]2 years ago
7 0
The gram-formula mass of citric acid is 3(1)+6(12)+5(1)+16(7)=192 g/mol.

This means that in 13.00 grams of citric acid, there are 13.00/192 = 0.067 moles.

From the equation, we know that for every 1 mole of citric acid that is consumed, 3 moles of carbon dioxide are produced.

This means that there are 3(0.067)=0.203 moles.

Since the gram-formula mass of carbon dioxide is 12+2(16)=44 g/mol, meaning it has a mass of 0.203(44)=8.93 g
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