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ira [324]
3 years ago
11

The smallest particle to retain the properties of an element is an?

Chemistry
1 answer:
svlad2 [7]3 years ago
4 0
I’m so sorry explain it more
You might be interested in
Compare melting point freezing point and boiling point
Tresset [83]
Melting point- the temperature at which a substance has changed from a solid to a liquid
freezing- the temperature at which a substance chanes from liquid to a solid
boiling point- the temperature at which a substance changes from a liquid to a gas phase
4 0
3 years ago
Which phrase best describes activation energy? (1 point)
iren [92.7K]

Answer: the minimum amount of energy required to break bonds and start a chemical reaction

Explanation: got a 100% on the quick check

8 0
2 years ago
Which statement about climate is true?
Y_Kistochka [10]
I believe the answer is B!
6 0
3 years ago
Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu
oksano4ka [1.4K]

Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, K=\frac{[B]}{[A]}>1

As, both 5000 and 8\times 10^{7} are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0
3 years ago
Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a
mel-nik [20]

Heat required : 4.8 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat needed to raise the temperature

Q = m . c . Δt

1. heat to raise temperature from -20 °C to 0 °C

\tt Q=10\times 2.09\times (0-(-20)=418~J

2. phase change(ice to water)

\tt Q=10\times 333=3330~J

3. heat to raise temperature from 0 °C to 25 °C

\tt Q=10\times 4.18\times (25-0)=1045~J

\tt Q~tot=418+3330+1045=4793~J\rightarrow rounding~and~2~sig~figs=4.8~kJ

3 0
3 years ago
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