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aksik [14]
4 years ago
5

A pump is used to transport water from a reservoir at one elevation to another reservoir at a higher elevation. If the elevation

difference increases by four times, the pump power required:
A) Increases by two times

B) Increases by four times

C) Increases by eight times

D) Increases by sixteen times
Engineering
1 answer:
erastova [34]4 years ago
4 0

Answer:b

Explanation:

We know power delivered by Pump is

P=\rho \times Q\times g\times \Delta H

where P\rho=Density of fluid

Q=Flow rate

g=acceleration due to gravity

\Delta H=Change in Elevation

If \Delta H is increased by 4 time then

P'=\rho \times Q\times g\times (4\Delta H)

P'=4 P

So power increases by four times.

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6 0
2 years ago
Pls help me it’s due today
hichkok12 [17]

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

6 0
3 years ago
Two rods, with masses MA and MB having a coefficient of restitution, e, move along a common line on a surface, figure 2. a) Find
ahrayia [7]

Answer:

A.) Find the answer in the explanation

B.) Ua = 7.33 m/s , Vb = 7.73 m/s

C.) Impulse = 17.6 Ns

D.) 49%

Explanation:

Let Ua = initial velocity of the rod A

Ub = initial velocity of the rod B

Va = final velocity of the rod A

Vb = final velocity of the rod B

Ma = mass of rod A

Mb = mass of rod B

Given that

Ma = 2kg

Mb = 1kg

Ub = 3 m/s

Va = 0

e = restitution coefficient = 0.65

The general expression for the velocities of the two rods after impact will be achieved by considering the conservation of linear momentum.

Please find the attached files for the solution

6 0
3 years ago
To find the quotient of 8 divided by 1/3, multiply 8 by?
iVinArrow [24]

Answer: 8.33333333 or 6.1989778

Explanation:

8 0
2 years ago
A sensor produces a signal with amplitude 15 mV. A voltage amplifier must amplify the signal such that the amplitude of the outp
Nady [450]

Answer:

42.50 dB

Explanation:

Determine the minimum voltage gain

amplitude of input signal ( Vi ) = 15 mV

amplitude of output signal ( Vo) = 2 V

Vo = 2 v

therefore ; minimum gain = Vo / Vi =  2 / ( 15 * 10^-3 )

                                                         = 133.33

Minimum gain in DB = 20 log ( 133.33 )

                                  = 42.498 ≈ 42.50 dB

8 0
3 years ago
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