Answer:
113.58 m
Explanation:
Range = Maximum Height

tan θ = 4
θ = 76 degree
Let u be the velocity of projection
K = 1/2 x m x u^2
1150 = 0.5 x 0.97 x u^2
u = 48.7 m/s
Range = [tex]\frac{u^{2}Sin2\theta }{g}
R = (48.7 x 48.7 x 2 x Sin 76 x Cos 76) / 9.8 = 113.58 m
7.5m/s (2.5 x 3) c = frequency x wavelength
Answer: D
Explanation: Look at the figure, we can conclude that the correct answer is
X: Low potential energy
Y: High potential energy
Z: Flow of electrons
Because electrons flow where there is difference in potential energy. And electrons move from a region of high potential energy to a region of low potential energy.
Since the arrow is pointing to X, that means
Z is the flow of electrons, X is of low potential energy and Y is of high potential energy.
Answer:
Final velocity is 181.61 m/s at angle 40.44° below horizontal.
Explanation:
Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s
Final horizontal velocity = 138.23 m/s
Considering vertical motion of projectile:
Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s
Acceleration, a = -9.81 m/s²
Displacement, s = -208 m
We have v² = u² + 2as
Substituting
v² = 98.96² + 2 x -9.81 x -208
v = 117.79 m/s
Final velocity,


Final velocity is 181.61 m/s at angle 40.44° below horizontal.