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riadik2000 [5.3K]
3 years ago
14

1. A box contains 10 blue chips. 5 red chips, and 15 yellow chips. Find the odds of choosing the

Physics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

Explanation:

Blue: 10/30

Red: 5/30

Yellow: 15/30

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Which type of error is a false positive
maks197457 [2]

Answer: Type I Error

5 0
2 years ago
The initial kinetic energy imparted to a 0.97 kg bullet is 1150 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air re
lys-0071 [83]

Answer:

113.58 m

Explanation:

Range = Maximum Height

\frac{u^{2}Sin2\theta }{g}=\frac{u^{2}Sin^{2}\theta }{2g}

tan θ = 4

θ = 76 degree

Let u be the velocity of projection

K = 1/2 x m x u^2

1150 = 0.5 x 0.97 x u^2

u = 48.7 m/s

Range = [tex]\frac{u^{2}Sin2\theta }{g}

R = (48.7 x 48.7 x 2 x Sin 76 x Cos 76) / 9.8 = 113.58 m

6 0
4 years ago
If the wavelength of a wave is 2.5 m, and its frequency is 3 Hz, what is its speed?
castortr0y [4]
7.5m/s (2.5 x 3) c = frequency x wavelength
3 0
3 years ago
Which labels best complete the diagram?
nlexa [21]

Answer: D

Explanation: Look at the figure, we can conclude that the correct answer is

X: Low potential energy

Y: High potential energy

Z: Flow of electrons

Because electrons flow where there is difference in potential energy. And electrons move from a region of high potential energy to a region of low potential energy.

Since the arrow is pointing to X, that means

Z is the flow of electrons, X is of low potential energy and Y is of high potential energy.

6 0
4 years ago
A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s
sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

Considering vertical motion of projectile:

Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

             v² = 98.96² + 2 x -9.81 x -208

             v = 117.79 m/s

Final velocity,

            v=\sqrt{138.23^2+117.79^2}=181.61m/s

            \theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0
4 years ago
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