A student jobs around a square park two times. Starting and ending at the gate to the park. The square jogging track is 40 meter
2 answers:
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Answer:
Percentage change in tension is 3.8%
Explanation:
We have given initially frequency = 440 Hz
Let tension in the string at this frequency is
Now second frequency is
Frequency in string is given by
From the relation we can say that
Percentage change in tension is equal to
%
So percentage change in tension is 3.8%
Define unit vectors as follows:
is in the eastern direction.
is in the northern direction.
The position of the first bird is
The position of the second bird is
Let θ = the angle between the net displacement vector for the two birds.
By definition,
Similarly,
|b| = 4.025
Therefore
Answer: 36.9°
The position of the first bird is
The position of the second bird is
Let θ = the angle between the net displacement vector for the two birds.
By definition,
Similarly,
|b| = 4.025
Therefore
Answer: 36.9°
Hope it helps............
