Answer:
λ1 = 0.0129m = 1.29cm
λ2 = 0.00923m = 0.92 cm
Explanation:
To find the distance between the first order bright fringe and the central peak, can be calculated by using the following formula:
(1)
m: order of the bright fringe = 1
λ: wavelength of the light = 660 nm, 470 nm
D: distance from the screen = 5.50 m
d: distance between slits = 0.280mm = 0.280 *10^⁻3 m
ym: height of the m-th fringe
You replace the values of the variables in the equation (1) for each wavelength:
For λ = 660 nm = 660*10^-9 m

For λ = 470 nm = 470*10^-9 m

Answer:
1/f = 1/i + 1/o thin lens equation
1/i = 1/f - 1/o
i = o * f / ( o - f) = 50 * (-20) / (50 - (-20)) = -14.3 cm
The final image is erect and 14.3 cm behind the curved surface
M = -o / i = 14.3 / 50 = .29 magnificaton of object
S = .29 * 25 cm = 7.1 cm appearance of bird in mirror (height)
Answer:
Change in momentum is 1.1275 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 274 g = 0.274 kg
It hits the floor and rebounds upwards.
The ball hits the floor with a speed of 2.40 m/s i.e. u = -2.40 m/s (-ve because the ball hits the ground)
It rebounds with a speed of 1.7 m/s i.e. v = 1.7 m/s (+ve because the ball rebounds in upward direction)
We have to find the change in the ball's momentum. It is given by :




So, the change in the momentum is 1.1275 kg-m/s
Answer:
The essential characteristics of an object in equilibrium is acceleration of the object must be zero.
Explanation:
Equilibrium: An object acted upon by several forces is said to be in equilibrium if it does no it moves or rotate. Equilibrium can be defined as the state of stability of an object.
Condition for equilibrium
(i) The resultant force acting on the object must me equal to zero.
(ii) The sum of moment acting on the object must be equal to zero.
But.
F = ma..................... Equation 1
Where F = net force , m = mass, a = acceleration.
from the equation above,
For F = 0 N, a must be equal to zero.
<em>From the above, the essential characteristics of an object in equilibrium is acceleration must be zero</em>
Answer:
The pressure in the water is 
Explanation:
Given that,
Depth = 101 m
Let P be the pressure at the bottom of water at a depth
We need to calculate the pressure in water
Using formula of pressure

Where,
= atmospheric pressure
= pressure in water
Put the value of
in to the formula

Put the value into the formula


Hence, The pressure in the water is 