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Tems11 [23]
2 years ago
6

Kendall has empty graduated cylinder with markings and an identical graduated cylinder partway filled with water. She also has a

balance and a marble.
Which statement best describes what Kendall can do?
A.She can measure the volume and mass of the marble, the volume and mass of the water, and the volume and mass of the graduated cylinder.
B.She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.
C.She can measure the volume of the marble and water, and the mass of the graduated cylinder.
D.She can measure the mass of the marble and water, and the volume of the graduated cylinder.
Physics
2 answers:
gtnhenbr [62]2 years ago
6 0

Answer:

The answer is B

Explanation:

Elis [28]2 years ago
4 0
The answer is B.
She can measure the mass of the water, marble and the graduated cylinder with the balance.
The volume of the water can be shown on the marked graduated cylinder, the volume of the marble can be measured by the volume difference of the water before and after the marble is put in.
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A 1.0 kg red superball moving at 5.0 m/s collides head-on with stationary blue superball of mass 4.0 kg in an elastic collision.
STatiana [176]
Initial conditions:
m1 = 1.0 ; v1 = 5
m2 = 4.0 ; v2 = 0

In the case where the second object (sometimes called the target) is at rest the velocities after the condition are

v1' = v1* (m1-m2)/(m1+m2)
v2' =  2v1*m1/(m1+m2)

For this we get
v1' = 5*(-3)/5 = -3m/s  (moving in the opposite direction as before at 3m/s
v2' = 2*5*(1)/5 = 2m/s in the same direction as the original ball was moving
you can see these directions by looking at the signs.  The momenta also add to the initial momentum as required.
5 0
3 years ago
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You are taking a turn at 30.0 m/s on a ramp of radius 25.0 m. What is your acceleration?
Nat2105 [25]

Acceleration = v^2 / r

Acceleration = 30^2/25

Acceleration = 900/25

Acceleration = 36 m/s^2

6 0
2 years ago
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 79.6 m/s at ground level.
Dimas [21]

Answer:

The rocket is motion above the ground for 44.7 s.

Explanation:

The equations for the height of the rocket are as follows:

y = y0 + v0 · t + 1/2 · a · t²

and, after the engine fails:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rocket at time t

y0 =  initial height

v0 = initial speed

t=  time

a = acceleration due to the engines

g = acceleration due to gravity

First, let´s calculate the time the rocket is being accelerated by the engines:

(The center of the framer of reference is located at the ground, y0 = 0).

y = y0 + v0 · t + 1/2 · a · t²

1190 m = 0 m + 79.6 m/s · t + 1/2 · 4.10 m/s² · t²

0 = 2.05  m/s² · t² + 79.6 m/s · t - 1190 m

Solving the quadratic equation:

t = 11.5 s  (the other value of t is discarded because it is negative).

At that time, the engines fail and the rocket starts to fall. The equation of the height will be:

y = y0 + v0 · t + 1/2 · g · t²

The initial velocity (v0) will be the velocity acquired during 11.5 s of acceleration plus the initial velocity of launch:

v = v0 + a · t

v = 79.6 m/s + 4.10 m/s² · 11.5 s

v = 126.8 m/s

Now, we can calculate the time it takes the rocket to reach the ground (y = 0) from a height of 1190 m:

y = y0 + v0 · t + 1/2 · g · t²

0 m = 1190 m + 126.8 m/s · t - 1/2 · 9.80 m/s² · t²

Solving the quadratic equation:

t = 33.2 s

Then, the total time the rocket is in motion is (33.2 s + 11.5 s) 44.7 s

 

5 0
3 years ago
Energy Transformation
Serjik [45]

Answer:

<em>K =400000 J</em>

Explanation:

<u>Kinetic Energy</u>

Is the energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

The car has a mass of m=2000 Kg and travels at v=20 m/s. Calculating the kinetic energy:

\displaystyle K=\frac{1}{2}2000*20^2

Calculating:

K =400000 J

3 0
3 years ago
Two skaters, a man and a woman, are standing on ice. Neglect any friction between the skate blades and the ice. The mass of the
IRISSAK [1]

Answer:

a₁ = 0.63 m/s²  (East)

a₂ = -1.18 m/s²  (West)

Explanation:

m₁ = 95 Kg

m₂ = 51 Kg

F = 60 N

a₁ = ?

a₂ = ?

To get the acceleration (magnitude and direction) of the man we apply

∑Fx = m*a   (⇒)

F = m₁*a₁         ⇒      60 N = 95 Kg*a₁    

⇒  a₁ = (60N / 95Kg) = 0.63 m/s²  (⇒)  East

To get the acceleration (magnitude and direction) of the woman we apply

∑Fx = m*a   (⇒)

F = -m₂*a₂         ⇒      60 N = -51 Kg*a₂    

⇒  a₂ = (60N / 51Kg) = -1.18 m/s²  (West)

For every case we apply Newton’s 3 d Law

8 0
3 years ago
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