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katen-ka-za [31]
3 years ago
12

A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s . what work did the shot-putter do on the ball?

Physics
1 answer:
garri49 [273]3 years ago
6 0
<span>1.0x10^3 Joules The kinetic energy a body has is expressed as the equation E = 0.5 M V^2 where E = Energy M = Mass V = Velocity Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion E = 0.5 * 7.2 kg * (17 m/s)^2 E = 3.6 kg * 289 m^2/s^2 E = 1040.4 kg*m^2/s^2 E = 1040.4 J So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>
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maxonik [38]
<h3>Answer:</h3>

209.236 kg · m/s

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: P = mv

  • P is momentum (in kg · m/s)
  • m is mass (in kg)
  • v is velocity (in m/s)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

<u>Step 2: Find Momentums</u>

<em>Football Player</em>

  1. Substitute [MF]:                    P = (87.2 kg)(2.87 m/s)
  2. Multiply:                                P = 250.264 kg · m/s

<em>Bullet</em>

  1. Substitute [MF]:                    P = (0.0520 kg)(789 m/s)
  2. Multiply:                                P = 41.028 kg · m/s

<u>Step 3: Find difference</u>

  1. Define equation:                    P₁ - P₂
  2. Substitute:                              250.264 kg · m/s - 41.028 kg · m/s
  3. Subtract:                                 209.236 kg · m/s
3 0
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Answer:

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Explanation:

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Answer:

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Explanation:

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Answer:

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Explanation:

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