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Tamiku [17]
3 years ago
6

An unknown galaxy has a large flattened core. Which of the following classifications would best fit this galaxy's description? I

rregular Spiral Lens Elliptical
Physics
2 answers:
Alja [10]3 years ago
7 0

Answer:

Spiral

i know it is so dont say nun people

Explanation:

olga nikolaevna [1]3 years ago
4 0

Answer:

Lens

Explanation:

A lens galaxy has a large flattened core.

Spiral has arms.

Elliptical is a perfect sphere.

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asambeis [7]

Explanation:

That's because the Sun's acceleration is much smaller

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A wave is a disturbance that carries from one place to another through matter of space
krok68 [10]

There's supposed to be a blank in the statement, where the answer is supposed to be inserted.

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4 0
3 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

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The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
What course the colour of silt soil?
Nata [24]

Answer:

Beige to black.

Explanation:

:)

3 0
3 years ago
Please help me !! i’ll mark brainliest if you’re right!
navik [9.2K]
Option 2nd is the answer
3 0
3 years ago
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