To draw the lewis structure of the ion <span>Ch3Ch2NH3+ given, we must know the number of bonds each element in the compound. C can have four bonds, H can only have 1 bond and N can have 5 bonds. In this case, first C has 3 H bonds and 1 C bond.The second C is bonded to the other C, 2 H's, and 1 N. N capable of 5 bonds is bonded to one C and 3 H's. The lacking one bond is reflected on the positive charge of the compound. </span>
This balanced equation shows us the ratios of reactants and products, so for every 3 oxygen molecules, we see that 4 iron atoms react as well. The answer is 4.
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Al + HCl → H₂ + AlCl₃
Balance Cl.
1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.
Al + 3HCl → H₂ + AlCl₃
Balance H.
3 on the left, 2 on the right. We have to start by multiplying everything else by 2.
2Al + 3HCl → 2H₂ + 2AlCl₃
Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.
2Al + 4HCl → 2H₂ + 2AlCl₃
Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.
2Al + 6HCl → 2H₂ + 2AlCl₃
Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.
2Al + 6HCl → 3H₂ + 2AlCl₃
Balance Al.
2 on the left, 2 on the right. Already balanced.
Here is our final balanced equation:
2Al + 6HCl → 3H₂ + 2AlCl₃
Hope this helps!
Answer:
PHOSPHITE ION is the correct answer.
Explanation:
Hope this helped Mark BRAINLIEST!!!