Your answer is B.
Because it says that that carbon burns in presence of oxygen (C+O) which is equal ( => ) to Carbon Dioxide (
)
Because it says that that carbon burns in presence of oxygen (C+O) which is equal ( => ) to Carbon Dioxide (
Gastric acid plays a key role in the digestion of proteins by activating digestive enzymes and often has a pH value in the range
1 answer:
If the pH of the acid at a given time is found to be 1.25, then the molarity of the gastric acid juice is 0.056M.
<h3>What is pH?</h3>pH is define as the negative logarithm of the concentration of H⁺ ions present in any solution and it will be represented as:
pH = -log[H⁺]
Concentration will be present in the form of molarity and pH value for gastric acid is given 1.25 means it is strong acid as it completely dissociates into their ions.
Required equation for calculation will be:
[H⁺] =
[H⁺] =
[H⁺] = 0.056 M
Hence molarity of the gastric acid juice is 0.056M.
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Answer:
molar composition for liquid
xb= 0.24
xt=0.76
molar composition for vapor
yb=0.51
yt=0.49
Explanation:
For an ideal solution we can use the Raoult law.
Raoult law: in an ideal liquid solution, the vapor pressure for every component in the solution (partial pressure) is equal to the vapor pressure of every pure component multiple by its molar fraction.
For toluene and benzene would be:
Where:
is partial pressure for benzene in the liquid
is benzene molar fraction in the liquid
vapor pressure for pure benzene.
The total pressure in the solution is:
And
Working on the equation for total pressure we have:
Since
We know P and both vapor pressures so we can clear from the equation.
So
To get the mole fraction for the vapor we know that in the equilibrium:
So
Something that we can see in these compositions is that the liquid is richer in the less volatile compound (toluene) and the vapor in the more volatile compound (benzene). If we take away this vapor from the solution, the solution is going to reach a new state of equilibrium, where more vapor will be produced. This vapor will have a higher molar fraction of the more volatile compound. If we do this a lot of times, we can get a vapor that is almost pure in the more volatile compound. This is principle used in the fractional distillation.
Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ =
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M