N₂O
N = 14.01 amu
O ≈ 16 amu
14.01 × 2 = 28.02 ; 2 Nitrogen
44.02 - 28.02 = 16 ; 1 Oxygen
Check
28.02 + 16 ≈ 44.02amu
10 moles of H2 reacts with 5 moles of O2 creating 10 moles of water.
Water has the molar mass 18 g/mole
10 · 18g = 180 g
180 g of water can be produced from 10 moles of hydrogen gas.
Answer:

Explanation:
Hello there!
In this case, since the combustion of butane is:

Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:

Best regards!
Answer: can i see the whole paper
Explanation: