Molar mass:
O₂ = 32.0 g /mol CH₄ = 16.0 g/mol
2 O₂ + CH₄ = CO₂ + 2 H₂O
2 x 32 g O₂ ---------------> 16 g CH₄
100 g O₂ ------------------> ( mass of CH₄)
mass of CH₄ = 100 x 16 / 2 x 32
mass of CH₄ = 1600 / 64
= 25 g of CH₄
hope this helps!
Answer:
2 molecules of water represents 3.32 x 10^-24 moles of water.
Explanation:
To find the solution to this problem, you have to use the concept of Avogadro´s number, that is in 1 mol of any element o compound there are 6.022 x 10^23 molecules. Then,
1 mol H2O ------------- 6.022 x 10^23 molecules
x= 3.32 x 10^-24 ---- 2 molecules.
2 molecules of water represents 3.32 x 10^-24 moles of water.
Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane