2 years ago

if the distance moved by the effort is greater than the distance moved by the load, the machine is speed multiplier. TRUE/FALSE

Physics

1 answer:

just olya [345]2 years ago

4 0

Answer: TRUE

Explanation: I did it before

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What will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors?

dsp73

Hello!

Recall for resistors in parallel:
$\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}$

We can begin by calculating the total resistance:
$\frac{1}{R_t} = \frac{1}{10} + \frac{1}{10} + \frac{1}{10}}\\\\\frac{1}{R_t} = \frac{3}{10}\\\\R_t = \frac{10}{3} = \boxed{3.333 \Omega}$

Now, we can calculate the current using Ohm's Law:
$V = iR\\\\i = \frac{V}{R}$

V = Voltage of battery (V)
i = Current (A)

R = Resistance (Ω)

Plug in the given voltage and the total resistance we solved for.

$i = \frac{15}{3.33} = \boxed{4.5 A}$

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2 years ago

if the distance moved by the effort is greater than the distance moved by the load, the machine is speed multiplier. TRUE/FALSE​

if the distance moved by the effort is greater than the distance moved by the load, the machine is speed multiplier. TRUE/FALSE