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Alona [7]
2 years ago
7

A man invests $8 000 at 12% simple interest for 3 years. If he invests the same amount of money for the same time period at 12%

compound interest, what is the difference between the two investments?
Mathematics
1 answer:
AleksandrR [38]2 years ago
5 0

Answer:

  $359.42

Step-by-step explanation:

The difference in the investment values can be computed by making use of the formulas for the account balance in each case.

  compound interest: A = P(1 +r)^t . . . . interest at rate r compounded annually

  simple interst: A = P(1 +rt) . . . . simple interest at rate r

__

The account earning simple interest will have a balance of ...

  A = $8000(1 +0.12×3) = $10,880

The account earning compound interest will have a balance of ...

  A = $8000(1 +0.12)^3 ≈ $11,239.42

The difference between the two investments is ...

  $11,239.42 -10,880 = $359.42

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Answer:

47.33

Step-by-step explanation:

Hey there! I'm happy to help!

We have 8 bags of dog food and each costs $25.19

8(25.19)=201.52

And we have 11 leashes each costing $4.65.

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We add these totals up.

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We subtract this from 300 to see how much is left.

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Rhonda had $47.33 left after her purchases.

Have a wonderful day! :D

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Step-by-step explanation:

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Is 25% of a whole always the same amount ?
wel

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Not, will be the same proportion but the amount vary depending the specific case.

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Step-by-step explanation:

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