So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is
, with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:
y = 2x^2 − 4x + 12: 
y = 4x^2 + 8x + 3: 
In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.
Answer:
Step-by-step explanation:
<u>Exponential function:</u>
<u>Ordered pairs given:</u>
<u>Substitute x and y values to get below system:</u>
<u>Divide the second equation by the first one and solve for b:</u>
- 80/10 = b³
- b³ = 8
- b = ∛8
- b = 2
<u>Use the first equation and find the value of a:</u>
<u>The function is:</u>
Answer:
145
Step-by-step explanation:
just use a calculator
Answer:
40°
Step-by-step explanation:
Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.