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Darya [45]
2 years ago
13

Answer the following questions. When you have finished, submit this assignment to your teacher by the due date for full credit.

Chemistry
1 answer:
Stells [14]2 years ago
3 0

Answer:

1. chloroplast

2. they prevent some proteins to function how they normally function

Explanation:

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I hope this picture helps

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2 years ago
Solid carbon tetrachloride, CCl4(s), is represented by the diagram above. The attractions between the CCl4 molecules that hold t
Ne4ueva [31]

Hi, you've asked an incomplete question. Here's the diagram that completes the question.

Answer:

<u>(B) nonpolar covalent bonds</u>

Explanation:

This structure in the diagram rightly fits the description of a non-covalent bond because there is an equal sharing of electrons of Carbon (C) and Chlorine (Cl).

<em>Remember</em> too that these elements are in their solid-state, hence the CCl4 (carbon tetrachloride) molecules are held strongly together.

7 0
2 years ago
A block has a mass of 20g and measures 2cm*4cm*2cm, will it sink or float?
stich3 [128]
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5 0
2 years ago
As you have seen, ozone is formed in the upper atmosphere through the reaction:
baherus [9]

The rate law equation for Ozone reaction

r=k[O][O₂]

<h3>Further explanation</h3>

Given

Reaction of Ozone :.

O(g) + O2(g) → O3(g)

Required

the rate law equation

Solution

The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants

For reaction

aA + bB ⇒ C + D

The rate law can be formulated:

\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}

where

r = reaction rate, M / s

k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹

a = reaction order to A

b = reaction order to B

[A] = [B] = concentration of substances

So for Ozone reaction, the rate law (first orde for both O and O₂) :

\tt \boxed{\bold{r=k[O][O_2]}}

5 0
3 years ago
The diagram below shows the positions of the Earth, Moon, and Sun. What is the date?
Anna35 [415]
Answer is: <span>B) June 21.
This is summer solstice or midsummer.
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5 0
3 years ago
Read 2 more answers
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