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2 years ago

Compare your circulatory system to a busy street in a city or town.

Chemistry

1 answer:

White raven [17]2 years ago

7 0

City individuals -different cells. Group of individuals - Organ systems. City Road System- Circulatory system.

Explanation:

Any city has population. The individuals of the population can be considered as the cells that are present in a human body. As a city cannot be formed with individuals, the human body cannot survive without cells. These individuals will belong to different profession and they go to an organisation for doing various work.

These can be compared with the organ system of human body. These organ systems will be performing different functions. The network of any rod in a city can be compared with the circulatory system of human body. As it helps individuals to reach their home of any destination, the presence of arteries and veins can be compared with the highways and capillaries can be associated with side ways of the road system.

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The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this

nevsk [136]

Answer:

$5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}$

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

$Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }$

The given reaction involves the decomposition of H2O into H2 and O2

$2H_{2}O\rightleftharpoons 2H_{2} + O_{2}$

The equilibrium constant is expressed as :

$Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}$

Since Keq = 5.31*10^-10

$5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}$

3 0

2 years ago

Read 2 more answers

How to Calculate the de Broglie wavelength for each of the following ? a. an electron with a velocity 10.% of the speed of light

qaws [65]

H = planks constant
m = mass of the object 
u = velocity of the object 

h = 6.626 * 10^-34 J/s 
the mass of an electron is 9.12*10^-31 kg 
10% speed of light = 10% * 3*10^8 = 3*10^7 m/s, i dont have my graphing calc with me right now so i leave the technicalities up to you

8 0

3 years ago

A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t

Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

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2 years ago

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FromTheMoon [43]

Whats the question? I need to know to help....

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2 years ago

Organic chemistry too eazy but why 90% students avoid ?

Kruka [31]

Answer:

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2 years ago