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MariettaO [177]
3 years ago
13

Once formed, how are coordinate covalent bonds different from other covalent bonds?

Chemistry
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

\boxed {\boxed {\sf {One \ atom \ donates \ both \ electrons \ in \ a \ pair}}}

Explanation:

A covalent bond involves the sharing of electrons to make the atoms more stable, and so they satisfy the Octet Rule (8 valence electrons).

Typically each atom contributes an electron to form an electron pair. This is a single bond. There are also double bonds (two pairs of electrons), triple bonds (three pairs of electrons), and coordinate covalent bonds.

Sometimes, to satisfy the Octet Rule and achieve stability, one atom contributes both of the electrons in an electron pair. This is different from other covalent bonds because usually each of the 2 atoms contributes an electron to make a pair.

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Answer:

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Explanation:

Chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + H₂O

Balanced chemical equation:

Ca(OH)₂ + H₂SO₄     →     CaSO₄ + 2H₂O

The given reaction is double displacement reaction in which anion and cation of both reactant exchanged with each other. Calcium hydroxide react with sulfuric acid and form calcium sulfate and water.

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6 0
2 years ago
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If you begin with 1250 grams of N2 and 225 grams of H2 in the reaction that forms ammonia gas (NH3), how much ammonia will be fo
barxatty [35]
N₂+3H₂⇒ 2NH₃
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1250 grams are</span><span> left when the maximum amount of ammonia is formed.</span>
8 0
3 years ago
Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% N
olga nikolaevna [1]

Answer:

π = 14.824 atm

Explanation:

wt % = ( w NaCL / w sea water ) * 100 = 3.5 %

assuming w sea water = 100 g = 0.1 Kg

⇒ w NaCl = 3.5 g

osmotic pressure ( π ):

  • π = C NaCl * R * T

∴ T = 20 °C  + 273 = 293 K

∴ C ≡ mol/L

∴ density sea water = 1.03 Kg/L....from literature

⇒ volume sea water = 0.1 Kg * ( L / 1.03 Kg ) = 0.097 L sln

⇒ mol NaCl = 3.5 g NaCL * ( mol NaCL / 58.44 g ) = 0.06 mol

⇒ C NaCl = 0.06 mol / 0.097 L = 0.617 M

⇒ π = 0.617 mol/L * 0.082 atm L / K mol * 293 K

⇒ π = 14.824 atm

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