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Alina [70]
3 years ago
9

If 1.546 g of copper was used by a student at the start of the lab, and 0.732 g of copper were obtained at

Chemistry
1 answer:
mash [69]3 years ago
8 0

Answer: Percent recovery is 47.34 %

Explanation:

Percent yield is defined as the ratio of experimental yiled to theoretical yield in terms of percentage.

{\text{ percent yield}}=\frac{\text{amount recovered}}{\text{total amount}}\times 100

Putting in the values we get:

{\text{ percent yield}}=\frac{0.732}{1.546}\times 100=47.34\%

Therefore, the percent recovery is 47.34 %

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You are examining the DNA sequences that code for the enzyme phosphofructokinase in skinks and Komodo dragons. You notice that t
jek_recluse [69]

Answer: D. Mutation in coding sequences are more likely to be deleterious to the organism than mutations in noncoding sequences.

Explanation: It was not likely to be that the coding sequences are replicated more often. The only possible explanation is that the mutations in coding is more likely to be deleterious to the organism than mutations because it is in a non coding sequence.

8 0
3 years ago
A radio technician measures the frequency of an AM radio transmitter. The frequency is 11979kHz. What is the frequency in megahe
Murljashka [212]

Answer:

11.979 MHz

Explanation:

f = \text{11979 kHz} \times \dfrac{\text{1 MHz}}{\text{1000 kHz}} = \textbf{11.979 MHz}

7 0
3 years ago
5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

7 0
3 years ago
Given the equation representing a solution equilibrium: BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq)
goldenfox [79]

Answer:

The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases

Explanation:

Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.

In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;

BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.

This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.

3 0
3 years ago
Calculate the mass in grams of each sample.<br> 4.88x10^20 H2O2 molecules
AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0
3 years ago
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