Answer:
34.51
Explanation:
k=1/2mv² is the kenetic energy equation to fill is in
k=[1/2(0.235)×50]²
R= (rou * L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou*25)/ 3.5*10^-6
25*rou = 2.6495*10^-6
rou= 1.0598*10^-7 ohm.m
Answer:
62 N
Explanation:
Sum of the forces on the toolbox:
∑F = ma
T − mg = ma
T = mg + ma
T = m (g + a)
T = (5.0 kg) (9.8 m/s² + 2.5 m/s²)
T = 61.5 N
Rounded to two significant figures, the force exerted by the rope is 62 N.
Answer:
The value is 
Explanation:
From the question we are told that
The frequency of each sound is
The speed of the sounds is 
The distance of the first source from the point considered is 
The distance of the second source from the point considered is 
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
![\phi_a = 2 \pi [\frac{a}{\lambda} + ft]](https://tex.z-dn.net/?f=%5Cphi_a%20%3D%20%202%20%5Cpi%20%5B%5Cfrac%7Ba%7D%7B%5Clambda%7D%20%20%2B%20ft%5D)
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
Here b is the distance o f the first wave from the considered point
Gnerally the phase diffencence is mathematically represented as
=> ![\Delta \phi = \frac{2\pi [ a - b]}{ \lambda }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%5Cpi%20%5B%20a%20-%20b%5D%7D%7B%20%5Clambda%20%7D)
Gnerally the wavelength is mathematically represented as

=> 
=> 
=> ![\Delta \phi = \frac{2* 3.142 [ 4.40 - 4.0 ]}{ 0.611 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%2A%203.142%20%5B%204.40%20-%204.0%20%5D%7D%7B%20%200.611%20%20%7D)
=> 