All categories

3 years ago

How much water is stored in polar ice caps glaciers and permanent snow

Physics

1 answer:

antoniya [11.8K]3 years ago

8 0

Answer:

1.7% is stored in the polar icecaps, glaciers, and permanent snow

Explanation:

70% of the Earth's surface is covered with water; However, only a small percentage, 0.025%, is suitable for human consumption. A limited resource whose demand, according to the forecasts of the Organization for Economic Cooperation and Development (OECD), will skyrocket up to 55% globally between 2000 and 2050.

In the attached infographic we observe that the total volume of water on Earth is 1,386 million cubic kilometers, of which<em> </em><u>1.7% is forming polar ice, cap glaciers and permanent snow</u>. 1,338 million cubic kilometers of that water is in seas and oceans, that is, 96.5% is in seas and oceans, that is, it is salt water that cannot be drunk.

Only 3.5% of the Earth's water is fresh, but of this percentage, only 1% of the Earth's fresh water flows through the river basins in the form of streams and rivers.

You might be interested in

1) Consider an electric power transmission line that carries a constant electric current of i = 500 A. The cylindrical copper ca

JulsSmile [24]

Answer:

t = 1.27 x 10⁹ s

Explanation:

First, we will find the volume of the wire:

Volume = V = AL

where,

A = Cross-sectional area of wire = πr² = π(1 cm)² = π(0.01 m)² = 3.14 x 10⁻⁴ m²

L = Length of wire = 150 km = 150000 m

Therefore,

V = 47.12 m³

Now, we will find the number of electrons in the wire:

No. of electrons = n = (Electrons per unit Volume)(V)

n = (8.43 x 10²⁸ electrons/m³)(47.12 m³)

n = 3.97 x 10³⁰ electrons

Now, we will use the formula of current to find out the time taken by each electron to cross the wire:

$I =\frac{q}{t}$

where,

t = time = ?

I = current = 500 A

q = total charge = (n)(chareg on one electron)

q = (3.97 x 10³⁰ electrons)(1.6 x 10⁻¹⁹ C/electron)

q = 6.36 x 10¹¹ C

$500\ A = \frac{6.36\ x\ 10^{11}\ C}{t}\\\\t = \frac{6.36\ x\ 10^{11}\ C}{500\ A}$

Therefore,

7 0

3 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3,400 rev/min. When switched off, it rotates through 52.0 re

eduard

The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².

<h3> Constant angular acceleration</h3>

Apply the following kinematic equation;

ωf² = ωi² - 2αθ

where;

ωf is the final angular velocity when the centrifuge stops = 0
ωi is the initial angular velocity
θ is angular displacement
α is angular acceleration

ωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s

θ = 52 rev x 2π rad/rev = 326.7 rad

0 = ωi² - 2αθ

α = ωi²/2θ

α = ( 356.05²) / (2 x 326.7)

α = 194.02 rad/s²

Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².

Learn more about angular acceleration here: brainly.com/question/25129606

#SPJ1

7 0

2 years ago

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.0

zloy xaker [14]

Answer: $278\ Hz$

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

$\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m$

Condition for destructive interference is

$\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}$

for second destructive interference; n=2

$\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz$

4 0

3 years ago

Example 4:

earnstyle [38]

Answer:

Given speed of light in diamond =1.24*10m/s

speed of light (c) =3*10^8m/s

refractive index of diamond =3*10^8/1.24*10=2.41*10^7m/s

3 0

3 years ago

Wich of the following celestial bodies is most likely to have many craters

Ede4ka [16]

Where are the following awnsers?

6 0

3 years ago