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mash [69]
4 years ago
10

A student pulls a box across a horizontal floor at a constant speed of 4.0 meters per second by exerting a constant horizontal f

orce of 45 newtons. approximately how much work does the student do against friction in moving the box 5.5 meters across the floor?
Physics
2 answers:
ruslelena [56]4 years ago
8 0
Work = Force multiplied by the distance(or displacement)
Rainbow [258]4 years ago
5 0

Answer:

247.5N

Explanation:

A student pulls a box across a horizontal floor at a constant speed of 4.0 meters per second by exerting a constant horizontal force of 45 newtons. approximately how much work does the student do against friction in moving the box 5.5 meters across the floor?

DEFINITION OF TERMS

work done is the product of force and distance. if the student pulls the box without covering a distance, e asnt done any form of work.

force is tat which tends to change a body's state of rest or uniform motion  in a straight line.

w=f*d

45*5.5

247.5Nm

the frictional force between the object and the ground will be in the opposite direction to the force applied

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URGENT!!!!! If a 6 Ω resistor is in a circuit connected to a voltage source, and the current through the circuit is 2 amps, what
Eduardwww [97]

Answer:

Explanation:

according to ohms law we know that

v=IR

given current =2 amps

given resistance =6Ω

so voltage is

v=2*6 =12 V

3 0
3 years ago
You have two points in a soil. Point A is at 75 cm; point B is at 25 cm above the reference. The capillary potential energy at p
user100 [1]

Answer:

The potential energy at point A is 17.1675 J

Explanation:

The capillary potential is the work expended to bring up a unit mass of liquid to a point in a capillary region from a level liquid surface. It is the capillary potential that facilitates the movement of moisture within soil capillaries

In meteorology it is used to describe the level of saturated soil above the water table

Potential energy is the energy inherent in a body by virtue of its position, therefore the potentials of both point A and B are

Point A, elevation = 75 cm capillary potential = -100 cm

Point B, elevation = 25 cm capillary potential = -200 cm

The total potential energy at point A is

Elevation above reference - capillary potential =75-(-100) = 175 cm

which gives per unit mass

PE = m × g × h = 1 kg × 9.81 m/s ² × 1.75 m = 17.1675 kg·m²/s² = 17.1675 J

8 0
3 years ago
A vase falls from a windowsill 50.0 m above the sidewalk. How fast is the base moving when it hits the ground?
scZoUnD [109]

Answer:

The answer is A sorry if i'm wrong

Explanation:

6 0
3 years ago
What is the approximate terminal velocity of a sky diver before the parachute opens
anzhelika [568]

Answer:

The approximate terminal velocity of a sky diver before the parachute opens is 320 km/h.

Explanation:

  • The terminal velocity is the maximum magnitude of velocity that is attained by the diver when he or she falls in the air.
  • The terminal velocity of the person diving in air before opening parachute is 320 km/h that means the velocity when the person is experiencing free fall is 320 km/h.
  • During terminal velocity, we can represent mathematical equation as;

                           Buoyancy force + drag force = Gravity

6 0
3 years ago
A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-
djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0
4 years ago
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