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inessss [21]
3 years ago
12

Which response includes all the following that are properties of most metals, and no other properties?

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

The correct options are: Z1) They tend to form cations, and Z4) They tend to form ionic compounds when they combine with the elements of Group VIIA.

Explanation:

The chemical elements that have a tendency of <u>losing their valence electrons</u> and are generally present on the <u>left-side of the periodic table</u> are known as metals.

The general characteristics of metals are malleability, ductility, lustre, high thermal and electrical conductivity.

The metals<u> readily lose their valence electrons</u> present in their valence electron shell to<u> form positively charged ions called </u><u>cation</u>s and thus have <u>low ionization energy</u>.

They also tend to form<u> </u><u>ionic compounds or salts</u><u> </u>with the <u>reactive non-metals belonging to the Group VIIA of the periodic table.</u>

<u>Therefore, </u><u>Z1 and Z4 </u><u>are the properties of most metals.</u>

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Which of the following can explain the daily change in sea level observed along a coast?
salantis [7]
The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide. 
5 0
3 years ago
For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

6 0
3 years ago
2 PUIS
avanturin [10]

Answer: C the study of living things

Explanation:

5 0
3 years ago
Read 2 more answers
PLEASEEEEEEEEEEEE HELPPPPPPPP I BEGGGGG FOR HELPPPPP
Elza [17]

Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

3 0
3 years ago
Compounds that have the exact same molecular formula but are arranged differently are<br> called?
Marysya12 [62]

Answer:

isomers

Explanation:

Compounds that have the same molecular formula but different chemical structures are called isomers. Remember isomerism is a property between a pair (or more) of molecules, i.e. a molecule is an isomer of another molecule.

3 0
3 years ago
Read 2 more answers
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