The mass of potassium chlorate, KClO₃ needed to produce 30 grams of potassium chloride, KCl is 49.33 grams
<h3>Balanced equation </h3>
2KClO₃ —> 2KCl + 3O₂
Molar mass of KClO₃ = 39 + 35.5 + (16×3) = 122.5 g/mol
Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g
Molar mass of Kcl= 39 + 35.5 = 74.5 g/mol
Mass of KCl from the balanced equation = 2 × 74.5 = 149 g
SUMMARY
From the balanced equation above,
149 g of KCl were obtained from 245 g of KClO₃
<h3>How to determine the mass of KClO₃ needed </h3>
From the balanced equation above,
149 g of KCl were obtained from 245 g of KClO₃
Therefore,
30 g of KCl will be obtained from = (30 × 245) / 149 = 49.33 g of KClO₃
Thus, 49.33 g of KClO₃ are needed for the reaction
Learn more about stoichiometry:
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