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2 years ago

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Chemistry

1 answer:

Wittaler [7]2 years ago

8 0

Answer:

Here is a set of possible answers:

By how much can CO2 emissions be reduced?

How much is it going to cost the city to install the wind farms?

Will families have to pay for part of the wind farms?

What is the out-of-pocket cost of installing solar panels on a house after the assistance has been granted?

Are there any yearly operating costs to use solar panels?

How reliable is solar energy in this area? In an average year, how many months can solar energy be used?

Do we have a backup source of energy if the wind farm or solar panels don’t generate enough electricity?

Explanation:

This is the actucal answer so you might want to change it up

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ASAP PLEASE

marishachu [46]

Answer:

Explanation:

the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

8 0

3 years ago

Read 2 more answers

A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

LenKa [72]

Answer:

$P=3.7atm$

Explanation:

Hello,

In this case, it is possible to determine the pressures of both helium and neon as shown below:

$n_{He}=\frac{P_{He}V_{He}}{RT}=\frac{5.6atm*3.0L}{0.082\frac{atm*L}{mol*K}*298.15K} =0.688molHe\\\\n_{Ne}=\frac{P_{Ne}V_{Ne}}{RT}=\frac{3.6atm*4.5L}{0.082\frac{atm*L}{mol*K}*298.15K}=0.663molNe$

Now, one considers the total moles (addition between both neon's and helium's moles) and the total volume to compute the final pressure as shown below:

$P=\frac{n_TRT}{V_T} =\frac{(0.688+0.663)mol*0.082\frac{atm*L}{mol*K}*298.15K}{9.0L}=3.7atm$

Best regards.

8 0

2 years ago

What is the name of MnO3

vodka [1.7K]

Answer:

MnO3 radical anion. Formula: MnO3- Molecular weight: 102.9368.

5 0

3 years ago

Read 2 more answers

How many moles of Manganese there in are 5.76 x 10(15) atoms of Mn?

aksik [14]

Answer:

1. 9.57 × 10^-9 moles.

2. 7.38mol

Explanation:

1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)

Hence, to find the number of moles (n) of Manganese (Mn), we say:

5.76 x 10^15 atoms ÷ 6.02 × 10^23

5.76/6.02 × 10^(15-23)

= 0.957 × 10^-8

= 9.57 × 10^-9 moles.

2.) Mole = mass/molar mass

Molar mass of sodium chloride (NaCl) = 23 + 35.5

= 58.5g/mol

mole = 431.6 g ÷ 58.5g/mol

mole = 7.38mol

7 0

2 years ago

(a) ions in a certain volume of .20M NaCl (aq) are represented in the box above on the left. in the box above on the right, draw

mamaluj [8]

Answer:

The first picture attached is the diagram that accompanies the question.

The<u> second picture attached</u> is the diagram with the answer.

Explanation:

In the box on the left there are 8 Cl⁻ ions and 8 Na⁺ ions.

The dissociaton equation for NaCl(aq) is:

NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)

The dissociation equation for CaCl₂ (aq) is:

CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.

Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half) and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).

Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.

4 0

2 years ago