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MAXImum [283]
2 years ago
14

Predict the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, S

8(s).
A) 1.5g Fe
B) 2.5g Fe
C) 3.5g Fe
D) 5.5g Fe
Chemistry
2 answers:
iVinArrow [24]2 years ago
7 0

answer is D.........

777dan777 [17]2 years ago
3 0
1) Chemical equation

16Fe(s) + 3S8(s) ---> 8Fe2S3

2) Molar ratios:

16 mol Fe : 3 mole S8 : 8 mol Fe2S3

3) Convert masses in grams to number of moles

number of moles = mass in grams / molar mass

a) iron, Fe

mass = 3.0 g
atomic mass = 55.845 g/mol

=> number of moles of Fe = 3.0g / 55.845 g/mol = 0.0537 mol

b) Sulfur, S8

mass = 2.5 g
molar mass = 8*32.065 g/mol = 256.52 g/mol

=> number of moles of S8 = 2.5g / 256.52 g/mol = 0.009746 mol

4) Limiting reactant

Theoretical ratio                           actual ratio

16 mol Fe / 3 mol S8                 0.0537 mol Fe / 0.009746 mol S8

5.33                                               5.50

So, there is a little bit more Fe than the theoretical needed to react all the S8, which means the S8 is the limiting reactant.

5) Calculate the number of moles of iron (III) produced with 2.5 g (0.009746 moles) of S8

3moles S8 / 8 moles Fe2S3 = 0.009746 moles S8 / x

=> x = 0.009746 * 8 / 3 moles Fe2S3 = 0.026 moles Fe2S3

6) Convert 0.026 moles Fe2S3 into grams

mass in grams = number of moles * molar mass

molar mass of Fe2S3 = 207.9 g/mol

mass = 0.026 mol * 207.9 g/mol = 5.40 g

7) Answer: option D)




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chubhunter [2.5K]

The concentration of the solution in units of molarity is 0.64 M and the concentration of the solution in terms of g/mL is 0.10976 g/mL.

<h3>What is the concentration of the solution?</h3>

The measure of the amount of the solute dissolved in the given amount of the solvent or solution is said to be the concentration of the solution.

It is given by the expression,

Concentration of the solution = mass of the solute/total volume of the solution

Units: g/mL

<h3>What is the concentration of the solution in units of molarity?</h3>

The concentration of the solution in units of molarity is given by the expression,

Molarity = (no. of moles of the solute)/(Volume in L)

Units: moles/L

<h3>Calculation:</h3>

It is given that the solute is barium hydroxide - Ba(OH)₂

The mass of Ba(OH)₂ = 2.81 g

When in dissolved in water, the total volume of the solution = 25.6 mL

The molar mass of Ba(OH)₂ = 171.34 g/mol

Then,

No. of moles = (mass of Ba(OH)₂)/(molar mass of Ba(OH)₂)

i.e.,

No. of moles = \frac{2.81}{171.34} = 0.0164 mole

Concentration = mass of the solute/total volume

I.e., C = \frac{2.81}{25.6} = 0.10976 g/mL

Then the concentration of the solution in units of molarity is,

Molarity = (no. of moles)/(Volume of the solution in L)

⇒ Molarity = \frac{0.0164}{25.6/1000} = 0.64 M

Therefore, the concentration of the solution in units of molarity is 0.64 M.

Learn more about molarity here:

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Sodium and chlorine combine to form table salt, also called sodium chloride. Sodium chloride is a(n) A. atom. B. element. C. com
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One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
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Answer:

The metallic oxide is Li₂O

Explanation:

Let the metallic oxide be M₂O

Thus;

M₂O + H₂ = 2M + H₂O

Molar mass of M₂O = (2x + 16)

We assume Molar mass of M to be x.

We are told that 5.00 g of the metallic oxide produces 2.32 g of the metal.

By proportion, we can write the following;

5g of M₂O × (1 mole of M₂O/(2x + 16)) × (2 moles of M/1 mole of M₂O) = 2.32 g of M × 1 mole of M/x g of M

This cancels out to give us;

10/(2x + 16) = 2.32/x

Cross multiply to get;

10x = 2.32(2x + 16)

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10x - 4.64x = 37.12

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x = 37.12/5.36

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nikdorinn [45]

There are 2.06 x 10²⁴ atoms

<h3>Further explanation </h3>

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1 mol = 6.02.10²³  particles

Moles can also be determined from the amount of substance mass and its molar mass

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