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s2008m [1.1K]
2 years ago
14

A force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the directio

n of the force calculate work done by:
(A)the horizontal component of force


(B)the vertical component of the force
Physics
1 answer:
anastassius [24]2 years ago
7 0

The work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

<h3>WORK </h3>

The work done on an object, is the product of the force F and the distance S in the direction of the force. That is,

W = F x S

The S.I unit of work is Joule

Given that a force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force

To calculate work done by:

(A) the horizontal component of force;

Force F = 36Sin55 = 29.489N

W = 29.489 x 64/100

W = 18.87 J

(B) the vertical component of the force;

Force F = 36Cos55 = 20.649

W = 20.649 x 64/100

W = 20.649 x 0.64

W = 13.22 J

Therefore, the work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

Learn more about Work here: brainly.com/question/8119756

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3 years ago
6.If a 250. gram cart moving to the right with a velocity of .31 m/s collides inelastically with a 500. gram cart traveling to t
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Answer:

The total momentum of the system before the collision is 0.0325 kg-m/s due east direction.    

Explanation:

Given that,

Mass of the cart, m = 250 g = 0.25 kg

Initial velocity of the cart, u = 0.31 m/s (due right)

Mass of another cart, m' = 500 g = 0.5 kg

Initial velocity of the another cart u' = -0.22 m/s (due left)

Let p is the total momentum of the system before the collision. It is given by :

p=mu+m'u'\\\\p=0.25\times 0.31+0.5\times (-0.22)\\\\p=-0.0325\ kg-m/s

So, the total momentum of the system before the collision is 0.0325 kg-m/s due east direction.            

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