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s2008m [1.1K]
2 years ago
14

A force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the directio

n of the force calculate work done by:
(A)the horizontal component of force


(B)the vertical component of the force
Physics
1 answer:
anastassius [24]2 years ago
7 0

The work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

<h3>WORK </h3>

The work done on an object, is the product of the force F and the distance S in the direction of the force. That is,

W = F x S

The S.I unit of work is Joule

Given that a force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force

To calculate work done by:

(A) the horizontal component of force;

Force F = 36Sin55 = 29.489N

W = 29.489 x 64/100

W = 18.87 J

(B) the vertical component of the force;

Force F = 36Cos55 = 20.649

W = 20.649 x 64/100

W = 20.649 x 0.64

W = 13.22 J

Therefore, the work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

Learn more about Work here: brainly.com/question/8119756

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In this problem, you will calculate the location of the center of mass for the Earth-Moon system, and then you will calculate th
Radda [10]

Answer:

a) Option D is correct.

The center of mass between the Eartg and the moon is inside the Earth.

Explanation:

Given,

Mass of the moon = (7.35×10²²) kg

Mass of the Earth = (6.00×10²⁴) kg

Mass of the Sun = (2.00×10³⁰) kg

Distance between the Earth and the moon = (3.80×10⁵) km

Distance between the Earth and the Sun = (1.50×10⁸) km

With the assumption that all.of the bodies being considered are on the same straight line on the x-axis,

Note that Centre of mass is given as

C.M = (Σmx)/(Σm)

For the Earth-moon system, let the earth be x=0, then the moon is at x = (3.80 × 10 5) km away.

C.M = (Σmx)/(Σm)

Σmx = (6.00×10²⁴)) × (0) + (7.35×10²²) × (3.80×10⁵) = (2.793 × 10²⁸) kg.km

Σm = (6.00×10²⁴) + (7.35×10²²) = (6.0735 × 10²⁴) kg

CM = (2.793 × 10²⁸) ÷ (6.0735 × 10²⁴)

CM = (4.60 × 10³) km = 4600 km

This means the centre of mass is 4600 km from the Earth.

The Earth's radius = 6378 km

Hence, the centre if mass is inside the Earth.

Hope this Helps!!!

8 0
3 years ago
Please help!
den301095 [7]

Hello there,

It takes 300 newtons of force and a distance of 20 meters for a moving cart to come to a stop. How much kinetic energy did this cart have?

Answer:  6000


8 0
3 years ago
What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.20 m whose potential is 240
Lady bird [3.3K]

Answer:

(a) charge q=5.33 nC

(b) charge density σ=10.62 nC/m²

Explanation:

Given data

radius r=0.20 m

potential V=240 V

coulombs constant k=9×10⁹Nm²/C²

To find

(a) charge q

(b) charge density σ

Solution

For (a) charge q

As

V_{potential}=kq/r\\ q=rV_{potential}/k\\q=\frac{(0.20)(240)}{9*10^{9} }\\ q=5.333*10^{-9}C\\or\\ q=5.33nC

For (b) charge density

As charge density σ is given as:

σ=q/(4πR²)

σ=(5.333×10⁻⁹) / (4π×(0.20)²)

σ=10.62 nC/m²

3 0
3 years ago
Which describes the changes in visible light moving from red to violet?
eimsori [14]
The wavelength decreases to roughly half.
(The frequency roughly doubles.)
3 0
3 years ago
What is an electron
Fiesta28 [93]

Answer:

C. A negative particle outside the nucleus

Explanation:

3 0
3 years ago
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