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s2008m [1.1K]
2 years ago
14

A force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the directio

n of the force calculate work done by:
(A)the horizontal component of force


(B)the vertical component of the force
Physics
1 answer:
anastassius [24]2 years ago
7 0

The work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

<h3>WORK </h3>

The work done on an object, is the product of the force F and the distance S in the direction of the force. That is,

W = F x S

The S.I unit of work is Joule

Given that a force of 36N acts at an angle of 55 degrees to the vertical. The force moves its point of application by 64 cm in the direction of the force

To calculate work done by:

(A) the horizontal component of force;

Force F = 36Sin55 = 29.489N

W = 29.489 x 64/100

W = 18.87 J

(B) the vertical component of the force;

Force F = 36Cos55 = 20.649

W = 20.649 x 64/100

W = 20.649 x 0.64

W = 13.22 J

Therefore, the work done by the horizontal component of force is 18.89 Joules while the vertical component of the force is 13.22 Joules.

Learn more about Work here: brainly.com/question/8119756

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How can you use distance and displacement to describe an object's motion​
andrew11 [14]

Answer:

distance can describe the total distance moved and displacement shows how far something has moved from its starting position (in a straight line from point a to point b) the object doesn't have to move in a straight line, but that is how displacement is measured

8 0
3 years ago
A 20-lb force acts to the west while an 80-lb force acts 45° east of north. The magnitu 80 lb 70 lb 067 lb 100 lb
natulia [17]

Answer:

option C

Explanation:

given,

force act on west  = 20 lb

force act at 45° east of north = 80 lb

magnitude of force = ?

∑ F y  =  80 cos 45⁰

    F y =  56.57 lb

magnitude of forces in x- direction

∑ F x = -20 + 80 sin 45⁰

        = 36.57 lb

net force

F = \sqrt{F_x^2+F_y^2}

F = \sqrt{56.57^2+36.57^2}

F = 67.36 lb≅ 67 lb

hence, the correct answer is option C

4 0
3 years ago
What is the mass of an object that is accelerated at 25 m/s2 by a force of 135 N?
yKpoI14uk [10]

Answer:

<h3>The answer is 5.4 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{135}{25}   =  \frac{27}{5} \\

We have the final answer as

<h3>5.4 kg</h3>

Hope this helps you

4 0
3 years ago
Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below. Overl
olga55 [171]

Answer:

A). A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil.

Explanation:

Scientists decided to change the model of the atom when they discovered new evidence that showed 'few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil.' On this ground, <u>Rutherford concluded that atom is mostly made up of empty space and thus, he proposed a nucleus model of atom in which the atom comprises of the tiny and positively charged nucleus is surrounded by electrons with a negative charge</u>. Thus, <u>option A</u> is the correct answer.

8 0
3 years ago
Read 2 more answers
what is the approximate weight of a 20-kg cannonball on the moon if the acceleration due to gravity is 1.6m/s^2
monitta
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons

BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N
5 0
3 years ago
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