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bazaltina [42]
2 years ago
15

As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The

farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?
Chemistry
1 answer:
weeeeeb [17]2 years ago
3 0

The electronic transition that will produce the lowest frequency is an electron falling from the 3rd to the 2nd energy level.

The question is incomplete, the complete question is;

As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?  

an electron falling from the 6th to the 2nd energy level  

an electron falling from the 5th to the 2nd energy level  

an electron falling from the 3rd to the 2nd energy level  

an electron jumping from the 1st to the 2nd energy level

According to Bohr's theory, energy is absorbed or emitted when an electron moves from one energy level to another. This energy often occurs as visible light of known frequency and wavelength.

The magnitude of frequency of light depends on the difference in energy between the two energy levels. If the difference between the energy levels is high, the frequency of light is also high and vice versa.

The transition from 3rd to the 2nd energy level represents a low frequency transition because the energy levels are close together.

Learn more: brainly.com/question/10675485

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Answer:

The symbol of isotopes used for blood flow analysis is \begin{array}{c}{141} \\ {58}\end{array} C e.

<u>Explanation: </u>

  • Isotopes are the substances that exhibit the same atomic number but has a different mass number of an element.
  • The atomic number explains the number of protons present in the element and mass number explains the number of neutrons available in the element.
  • For blood flow analysis, the isotope element is cerium-141 and it is used in the chemical examination of blood flow particles.
  • Symbol used for this isotope is \begin{array}{c}{141} \\ {58}\end{array} C e, where 141 indicates the amount of mass present and 58 indicates the proton number and 83 indicates neutron number present in that element.
  • The amount of mass in an atom is calculated by the sum of protons and neutrons present in it. Thus mass of isotope is 141 obtained by the sum of 58 protons and 83 neutrons present in that isotope.
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The electronic configuration of fluorine is 2,7.

Fluorine is the ninth element with a total of 9 electrons.

The first two electrons will go in the 1s orbital.

The next 2 electrons for F go in the 2s orbital.

The remaining five electrons will go in the 2p orbital. Therefore the F electron configuration will be 1s22s22p5.

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