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bazaltina [42]
2 years ago
15

As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The

farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?
Chemistry
1 answer:
weeeeeb [17]2 years ago
3 0

The electronic transition that will produce the lowest frequency is an electron falling from the 3rd to the 2nd energy level.

The question is incomplete, the complete question is;

As electrons fall from high energy orbitals to lower orbitals, energy is released in the form of electromagnetic radiation. The farther the electron falls, the more energy is released. Which of the following electronic transitions would produce a wave with the lowest frequency?  

an electron falling from the 6th to the 2nd energy level  

an electron falling from the 5th to the 2nd energy level  

an electron falling from the 3rd to the 2nd energy level  

an electron jumping from the 1st to the 2nd energy level

According to Bohr's theory, energy is absorbed or emitted when an electron moves from one energy level to another. This energy often occurs as visible light of known frequency and wavelength.

The magnitude of frequency of light depends on the difference in energy between the two energy levels. If the difference between the energy levels is high, the frequency of light is also high and vice versa.

The transition from 3rd to the 2nd energy level represents a low frequency transition because the energy levels are close together.

Learn more: brainly.com/question/10675485

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Given 50g of sodium how many moles do you have? ​
Anastaziya [24]

Answer:

Amount of Na = 2.17moles

Explanation:

Mass of Na = 50g

Molar mass of Na = 23g/mol

Amount of mole = mass/molar mass

Amount of mole = 50/23

Amount of mole = 2.17moles

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4 years ago
.<br> What energy transformations take place when you exercise?
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Quema de calorías que son parte de la energía interna de un cuerpo 

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3 years ago
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What is the volume of water in 150ml of the 35% of sucrose with a specific gravity of 1.115?
anzhelika [568]

Answer:

The volume of the water is 108.71 mL

Explanation:

Step 1: Data given

Volume of water =150 mL = 0.150 L

concentration of sucrose solution 35 % w/w this means in 100 grams of water we have 35 grams of sucrose

specific gravity =1.115

Step 2: Calculate the density of the solution

Density = specific gravity * density of water

Density of solution = 1.115 * 1g/ mL

Density of solution = 1.115 g/ mL

Step 3: Calculate mass of the solution

Mass of solution = density ¨volume

Mass of solution = 1.115 g/ mL * 150 mL

Mass of solution = 167.25 grams

Step 4: Calculate mass of sucrose

35 % = 0.35 * 167.25 grams

Mass sucrose = 58.54 grams

Step 5: Calculate mass of water

Mass of water = mass of sample - mass of sucrose

Mass of water = 167.25 - 58.54 = 108.71 grams

Step 6: Calculate volume of water

Volume = mass / density

Volume = 108.71 grams / 1g/ mL

Volume = 108.71 mL = 0.10871 L

The volume of the water is 108.71 mL

5 0
3 years ago
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A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL

Putting values in above equation, we get:

2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL

M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M

0.823 M was the molarity of the KOH solution.

7 0
3 years ago
GUYS I LITERALLY DONT DESERVE HIM I DO NOT DESERVE HIM IM DONE I CANT
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Just ignore such kind of people....

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