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Bogdan [553]
3 years ago
8

A block slides with no friction and hits a spring with spring constant k=2000 N/m. The block compresses the spring in a straight

line for a distance 0.15m. The block’s kinetic energy, in J, at that point is 0 J. What was its initial kinetic energy, in Joules?
Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

To solve this exercise it is necessary to apply the concepts related to kinetic energy in a spring.

By definition the kinetic energy keeping what is stipulated in the stable Hooke law that

KE_s = \frac{1}{2} kx^2

Where,

K = Spring constant

x = Displacement

Our values are given as,

x = 0.15m

k = 2000N/m

Therefore replacing

KE_s = \frac{1}{2} kx^2

KE_s = \frac{1}{2} (2000)(0.15)^2

KE_s = 22.5J

Therefore the initial kinetic energy is 22.5J

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Which occurs when a wave is reflected?
dmitriy555 [2]

Answer: The wave can flip upside down.

Reflection is the bending of a wave when it cannot pass through. For example, plain mirrors which are flat, a ray of light hits the mirror and is reflected from the mirror since it cannot pass through  

When reflection occurs the speed and frequency of the wave does not change but the wave is flipped upside down.

The speed does not change because speed is affected by the change in medium the frequency also remains the same since the energy of the wave does not change.


3 0
3 years ago
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When droplets of water in the atmosphere act like prisms, the colors in sunlight undergo?
dexar [7]
White light is all the colours of light combined. When the droplets act like prisms, they split the white light into all its colours and also slightly bend the different colours. This is how a rainbow is formed.
4 0
3 years ago
When the ignition is first turned on a click noise is heard from under the hood of a vehicle equipped with ETC. Technician A say
Ierofanga [76]

Answer:

Technician A says that this is the normal operation of the ETC self -test is the correct answer.

Explanation:

An engine control unit (ECU), also widely referred to as an engine control module (ECM), is a type of electronic control device that controls an internal combustion engine with a series of actuators to ensure maximum engine performance.

It achieves so by reading values from a multitude of sensors within the engine bay, translating data using multidimensional feedback maps (the so-called lookup tables) and modifying the actuators.

Mechanically fixed and dynamically regulated by mechanical and pneumatic means, air-fuel combination, ignition time, and idle speed were before ECUs.

As soon as the system gets battery voltage, after ignition is turned, the efi computer makes a self-test of all the actuators and sensors, included the ETC.

4 0
3 years ago
A function that assigns a numerical value to each outcome of an experiment is called
kozerog [31]

Random variable

Explanation:

A function that assigns a numerical value to each outcome of an experiment is described as a random variable. Random variables helps to determine the outcome of a random event.

  • Example of a random event is tossing of die, casting of a coin.
  • Random variables ascribe numerical values to the outcome of an experiment.
  • They are often used in probability to determine the extent of the certainty of an experimental procedure.

Learn more:

Probability brainly.com/question/1637111

#learnwithBrainly

8 0
3 years ago
A popular car stereo has four speakers, each rated at 60 W. In answering the following questions, assume that the speakers produ
Fantom [35]

Answer:

Explanation:

Intensity of sound = sound energy emitted by source / 4 π d² , where d is distance of the source .

A )

Intensity of sound at 1 m distance = 60 /4 π d²

d = 1 m

Intensity of sound at 1 m distance = 60 /(4 π 1²)

= 4.78 W m⁻² s⁻¹

B )

Intensity of sound at 1.5 m distance = 60 /4 π d²

d = 1.5  m

Intensity of sound at 1 m distance = 60 /(4 π 1.5²)

= 2.12 W m⁻² s⁻¹

C )

Intensity of sound due to 4 speakers at 1.5 m distance = 4 x 60 /4 π d²

d = 1.5  m

= 4 x 60 /(4 π 1.5²)

= 8.48 W m⁻² s⁻¹

D )

Intensity of sound due to .06 W speaker must be 10⁻¹² W s ⁻² . Let the distance be d .

.06 /4 π d² = 10⁻¹²

d² = .06 /4 π 10⁻¹²

d = 6.9 x 10⁴ m .

7 0
3 years ago
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