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ra1l [238]
2 years ago
12

a 3-newton force and a 4-newton force are acting concurrently on a point. which force could not produce equilibrium with these t

wo forces?
Physics
1 answer:
Paladinen [302]2 years ago
7 0

A force that cannot produce equilibrium with these two forces must be less than 7 N or greater 7 N.

The given parameters;

  • <em>3 Newton force </em>
  • <em>4 Newton force</em>

A body is said to be in equilibrium state when the net force on the body is zero.

A force that produce equilibrium among two forces acting concurrently is known as equilibrant force. This force is usually equal to sum of the two concurrent forces.

F_1 + F_2 = F_3

where;

  • F₁ and F₂ are the concurrent forces
  • F₃ is the equilibrant force

From the given parameters;

F_1 + F_2 = 3 \ N + 4\ N  = 7\ N

Thus, a force that cannot produce equilibrium with these two forces must be less than 7 N or greater 7 N.

Learn more here:brainly.com/question/12582625

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Answer:

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Explanation:

The charge transferred charge Q= −10nC = -10*10-9 C

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Number of electrons transferred:  N=\frac{Q}{Q_{e} }=(-10*10^{-9} )/(-1,602*10^{-19})=62421972534 electrons

5 0
3 years ago
What's the velocity for each trial? <br> And what's the average velocity?
adelina 88 [10]
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5 0
3 years ago
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the m
Akimi4 [234]

Answer:

8.6 m

Explanation:

The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration a=g=-9.8 m/s^2 towards the ground (we take upward as positive direction, so acceleration is negative).

The initial velocity along the vertical direction is

v_{y0} = v_0 sin \theta = (26 m/s)(sin 30^{\circ})=13 m/s

Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:

v_y(t)=v_{y0} +at

At the point of maximum height, v_y(t)=0, so we can find the time t at which the ball reaches the maximum height:

0=v_{y0}+at\\t=-\frac{v_{y0}}{a}=-\frac{13 m/s}{-9.8 m/s^2}=1.33 s

And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:

y(t)=v_{y0}t + \frac{1}{2}at^2=(13 m/s)(1.33 s)+\frac{1}{2}(-9.8 m/s^2)(1.33 s)^2=8.6 m

4 0
3 years ago
Astronaut Neil during his lunar mission recorded his weight. He noticed a big difference in his weight compared to his weight ta
Aleks [24]

Answer:

no entiendo

Explanation:

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6 0
3 years ago
Mr.G I running down the street trying to catch the bus. He is one city block away (200m) and this bus is leaving in 10s.
Sauron [17]

Answer:

a) 20 m/s

b) No

Explanation:

a)

Mr. G needs to run x= 200 m in t = 10 seconds to catch the bus.

Knowing the speed is computed as

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We have

\displaystyle v=\frac{200m}{10s}=20m/s

b)

The fastest human can run 12 m/s, so Mr. G won't be able to catch the bus because he needs to run faster than that

6 0
3 years ago
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