a 3-newton force and a 4-newton force are acting concurrently on a point. which force could not produce equilibrium with these t
1 answer:
A force that cannot produce equilibrium with these two forces must be less than 7 N or greater 7 N.
The given parameters;
- <em>3 Newton force </em>
- <em>4 Newton force</em>
A body is said to be in equilibrium state when the net force on the body is zero.
A force that produce equilibrium among two forces acting concurrently is known as equilibrant force. This force is usually equal to sum of the two concurrent forces.
where;
- F₁ and F₂ are the concurrent forces
- F₃ is the equilibrant force
From the given parameters;
Thus, a force that cannot produce equilibrium with these two forces must be less than 7 N or greater 7 N.
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Answer:
<em>The distance is 35 m and the magnitude of the displacement is 26.93 m</em>
Explanation:
<u>Displacement and Distance</u>
These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is calculated independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:
d = 25 m + 10 m = 35 m
To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.
The magnitude of the displacement is the distance from (0,0) to (-10,25):
D = 26.93 m
The distance is 35 m and the magnitude of the displacement is 26.93 m
Explanation:
It is known that relation between force and acceleration is as follows.
F =
I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.
F =
=
= 1430.625 N
Also, it is known that
= 7.70 degrees
Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.