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Nimfa-mama [501]
3 years ago
7

Molecules are not reacting using current methods. Which change can encourage a reaction?

Chemistry
1 answer:
matrenka [14]3 years ago
7 0

Adding heat to a system can encourage or increases a chemical reaction.

<h3>Change that can encourage a reaction</h3>

Increasing the temperature of a process, increase occurs in the average speed of the reactant molecules and we know that when more molecules move faster, the more number of molecules reacts with other molecules which results in faster formation of products.

In conclusion, adding heat is the right option.

Learn more about reaction here: brainly.com/question/26018275

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gregori [183]

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

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3 years ago
How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees Celsius to 80 degrees Celsius? (
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Water vapor condenses into a glass of water. The water is then placed in a freezer and changes into ice. What remains consistent
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Chemical properties
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Balance C2 H602+02 reacts with CO2 + H2O
sergiy2304 [10]

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8 0
4 years ago
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The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

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Therefore, the combustion of 1 mole of methane releases;

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Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

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