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gladu [14]
3 years ago
6

The compound potassium nitrate is a strong electrolyte. Write the transformation that occurs when solid potassium nitrate dissol

ves in water Use the pull-down boxes to specify states such as (aq) or (s).
Chemistry
1 answer:
trapecia [35]3 years ago
7 0

Answer:

The transformation that occurs when solid potassium nitrate dissolves in water:

KNO_3(s)\rightarrow K^+(aq)+NO_3^{-} (aq)

Explanation:

Electrolyte are those chemical compounds which oj dissolving water dissociates into ions and make the solution electrically conductive in nature.They are of two types:

  • Strong electrolytes: Those compounds which get complete dissociated into ions.
  • Weak electrolytes: Those compounds which get partially  dissociated into ions.

When solid potassium potassium nitrate is dissolved in water it get dissociated into potassium ions and nitrate ions in an aqueous solution :

KNO_3(s)\rightarrow K^+(aq)+NO_3^{-} (aq)

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sodium ions and chloride ions

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What causes the lines in the spectrum for elements? a continuous release of energy from the heated element a quantum absorption
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Answer:a quantum absorption of energy

Explanation:

Bohr’s model explains the spectral lines .While the electron of the atom remains in the ground state, its energy is unchanged. When the atom absorbs one or more quanta of energy, the electron moves from the ground state orbit to an excited state and when the atom relaxes back to a lower energy state, it releases energy that is again equal to the difference in energy of the two orbits.

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7.<br> How many grams are contained in 3.9 x 1023 sulfur atoms?<br> atoms → moles<br> grams<br> I
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What is the binding energy of a nucleus that has a mass defect of 5.81*10-^29 kg
IrinaVladis [17]

Answer:

Choice A: Approximately 5.23 \times 10^{-29} joules.

Explanation:

Apply the famous mass-energy equivalence equation to find the energy that correspond to the \rm 5.81\times 10^{-29} kilograms of mass.

E = m \cdot c^{2},

where

  • E stands for energy,
  • m stands for mass, and
  • c is the speed of light in vacuum.

The speed of light in vacuum is a constant. However, finding the right units for this value can simplify the calculations a lot. What should be the unit of c?

The mass given is in the appropriate SI unit:

Mass is in kilograms.

Thus, proceed with the speed of light in SI units. The SI unit for speed is meters per second. For the speed of light, c \approx \rm 3.00\times 10^{8}\;m\cdot s^{-1}.

Apply the mass-energy equivalence:

\begin{aligned} E &= m \cdot c^{2} \\ &= \rm 5.81\times 10^{-29}\; kg \times {\left(3.00\times 10^{8}\; m\cdot s^{-1}\right)}^{2}\\ &\approx \rm 5.23\times 10^{-12}\;kg\cdot m^{2}\cdot s^{-2} \end{aligned}.

The unit of energy is not in joules. Don't be alerted. Consider the definition of a joule of energy. One joule is the work done on an object when a force of one newton acts on the object in the direction of the force through the distance of one meter. (English Wikipedia.)

\rm 1\; J = 1\; N \times 1\; m.

However, a force of one newton is defined as the force required to accelerated an object with a mass of one kilogram (not gram) at a rate of one meter per second squared. (English Wikipedia.)

\begin{aligned}\rm 1\; J &= \rm 1\; N \times 1\; m\\ & = \rm \left(1\; kg\times 1\; m\cdot s^{-2}\right)\times 1\; m\\ &= \rm 1\; kg \cdot m^{2}\cdot s^{-2}\end{aligned}.

In other words, the mass defect here is also \rm 5.23\times 10^{-12}\; J.

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4 Quantum numbers are used

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