The value of C=1/3 for the probability density function f(x)=cx , 0<x<2.
<h3>What is probability density function?</h3>
The probability density function is a function of a continuous random variable, whose integral across an interval gives the probability that the value of the variable lies within the same interval.
Given that:
![f(x)=cx\ \ at\ 0 < x < 2](https://tex.z-dn.net/?f=f%28x%29%3Dcx%5C%20%5C%20at%5C%200%20%3C%20x%20%3C%202)
Here we can see that the value of x is varies as 0,1,2
So at 0,1,2 the value of the function is
![f(1)=c\times 1=c\\\\\\f(2)=c\times 2=2c\\\\](https://tex.z-dn.net/?f=f%281%29%3Dc%5Ctimes%201%3Dc%5C%5C%5C%5C%5C%5Cf%282%29%3Dc%5Ctimes%202%3D2c%5C%5C%5C%5C)
So the probability density function is given as:
![\sum f(x)=f(1)+F(2)=1\\\\\sum f(x)=c+2c=1](https://tex.z-dn.net/?f=%5Csum%20f%28x%29%3Df%281%29%2BF%282%29%3D1%5C%5C%5C%5C%5Csum%20f%28x%29%3Dc%2B2c%3D1)
![3c=1\\\\c=\dfrac{1}{3}](https://tex.z-dn.net/?f=3c%3D1%5C%5C%5C%5Cc%3D%5Cdfrac%7B1%7D%7B3%7D)
Hence the value of C=1/3 for the probability density function f(x)=cx , 0<x<2.
To know more about probability density function follow
brainly.com/question/14214648
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