How does the burning of fossil fuels increase the greenhouse effect answers?

Which of an atom's electrons are involved in chemical reactions?

Nadya [2.5K]

it’s C

i hope i help you but if not DO NOT FORGET STAY SAFE AT HOME

4 0

3 years ago

How many grams of glucose are in 11.5 moles?

mestny [16]

There are 2071.79 grams of glucose in 11.5 moles.

8 0

3 years ago

How do you draw a bohr diagram for a boron ion?

Otrada [13]

Because Boron likes to lose 3 electrons when it undergoes ionization, we draw a boron ion like a helium atom, with just 2 electrons in the first shell, and 0 in the second

5 0

3 years ago

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If the mass of a certain block is 500g, what is the weight of the block?

Dafna11 [192]

______________________________

Solution,

Mass=500g =500/1000=0.5 kg

gravity(g)=9.8m/s^2

Now,

Weight= m*g

 = 0.5*9.8

 =4.9 N

So the weight of the block is 4.9 Newton

hope it helps...

Good luck on your assignment

_______________________

5 0

3 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, n, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.

$w_\text{max} = n \cdot F \cdot E_\text{cell}$ , where

n is the number of moles electrons transferred,
F is the Faraday's constant,
E $_\text{cell}$ is the cell potential,

n = 0.144 mol, as shown above, and

F = 96.486 kJ / ( $\text{V} \cdot \text{mol} \; \text{e}^{-}$ ).

Therefore,

$w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}$ .

3 0

3 years ago