A gymnast with mass m1 = 44 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 =
109 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam.
1)What is the force the left support exerts on the beam?N
2)What is the force the right support exerts on the beam?N
3)How much extra mass could the gymnast hold before the beam begins to tip? kg
4)Now the gymnast (not holding any additional mass) walks directly above the right support. What is the force the left support exerts on the beam?N
5)What is the force the right support exerts on the beam?N
6)At what location does the gymnast need to stand to maximize the force on the right support?
a. at the center of the beam
b. at the right support
c. at the right edge of the beam
1)What is the force the left support exerts on the beam?N
2)What is the force the right support exerts on the beam?N
3)How much extra mass could the gymnast hold before the beam begins to tip? kg
4)Now the gymnast (not holding any additional mass) walks directly above the right support. What is the force the left support exerts on the beam?N
5)What is the force the right support exerts on the beam?N
6)At what location does the gymnast need to stand to maximize the force on the right support?
a. at the center of the beam
b. at the right support
c. at the right edge of the beam
1 answer:
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Answer:
gravitational force
electrostatic force
Explanation:
The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.
The Mutual force of gravitational pull that they exert on each other can be given as:
where:
gravitational constant
are the masses of individual balloons
the radial distance between the center of masses of the balloons.
But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.
Given as:
where:
are the charges on the individual balloons
R = radial distance between the charges.
Answer:
1.38 x 10^-18 J
Explanation:
q = - 1.6 x 10^-19 C
d = 5 x 10^-10 m
the potential energy of the system gives the value of work done
The formula for the potential energy is given by
So, the total potential energy of teh system is
As all the charges are same and the distance between the two charges is same so the total potential energy becomes
K = 9 x 10^9 Nm^2/C^2
By substituting the values
U = 1.38 x 10^-18 J
To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.
The linear mass density is given as,
The expression for the wavelength of the standing wave for the second overtone is
Replacing we have
The frequency of the sound wave is
Now the velocity of the wave would be
The expression that relates the velocity of the wave, tension on the string and linear mass density is
The tension in the string is 547N
PART B) The relation between the fundamental frequency and the harmonic frequency is
Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore
Then,
Rearranging to find the fundamental frequency