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leva [86]
3 years ago
9

A gymnast with mass m1 = 44 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 =

109 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam.
1)What is the force the left support exerts on the beam?N
2)What is the force the right support exerts on the beam?N
3)How much extra mass could the gymnast hold before the beam begins to tip? kg
4)Now the gymnast (not holding any additional mass) walks directly above the right support. What is the force the left support exerts on the beam?N
5)What is the force the right support exerts on the beam?N
6)At what location does the gymnast need to stand to maximize the force on the right support?

a. at the center of the beam
b. at the right support
c. at the right edge of the beam

Physics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

Explanation:

e. At the right edge of the beam

Check attachment for other solution

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FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

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Hence the distance travelled by the truck is 82.7 m

6 0
2 years ago
It is observed that the time for the ball to strike the ground at b is 2.5 s. determine the speed at which the ball was thrown.
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2 years ago
A mass attached to a spring vibrates back and forth. At maximum displacement, the spring force and the
Svetradugi [14.3K]

ANSWER

Velocity of the mass reaches zero

EXPLANATION

We want to identify what hapens to a mass attached toa a spring at maximum displacement.

When a mass attached to a spring is at its maximum position of displacement, the direction of the mass begins to change. This implies that the velocity of the mass will reach zero.

Hence, at maximum displacement, the velocity of the mass reaches zero.

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10 months ago
An electron moves with a speed of 8.0×106m/s along the -z-axis. It enters a region where there is a uniform magnetic field B = (
Crazy boy [7]

Answer:

Acceleration, a=9.36\times 10^{18}\ m/s^2

Explanation:

It is given that,

Speed of electron, v=8\times 10^6\ m/s

Charge on an electron, q=1.6\times 10^{-19}\ C

Mass of electron, m=9.1\times 10^{-31}\ kg

Magnetic field, B=5.5i-3.7j

Magnitude, |B|=\sqrt{5.5^2+(-3.77)^2}=6.66\ T

Magnetic force is given by :

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Also, F = ma

a=\dfrac{qvB}{m}

a=\dfrac{1.6\times 10^{-19}\times 8\times 10^6\times 6.66}{9.1\times 10^{-31}}

a=9.36\times 10^{18}\ m/s^2

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