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Artist 52 [7]
4 years ago
13

Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2

Chemistry
2 answers:
nexus9112 [7]4 years ago
7 0

Answer : The balanced chemical reaction will be,

2Na+2H_2O\rightarrow 2NaOH+H_2

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

a_0Na+a_1H_2O\rightarrow a_2NaOH+a_3H_2

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of hydrogen are not balanced while all the atoms are balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the Na,H_2O\text{ and }NaOH

Thus, the balanced chemical reaction will be,

2Na+2H_2O\rightarrow 2NaOH+H_2

Alexandra [31]4 years ago
4 0
Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

</span></span>Sodium<span> + </span>Dihydrogen Monoxide<span> = </span><span>Natriumhydroxid</span><span> + </span>Hydrogen

Coefficients:

Reagents  :  Na = 2
                    H2O = 2
   

Products :  NaOH = 2
                  H2 = 1
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The answer is A.

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3 years ago
Why is a lot of energy needed to break covalent bonds
gulaghasi [49]

Answer:

The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.

Explanation:

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3 years ago
A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC
inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0
3 years ago
Consider the model of the nitrogen atom.
liq [111]

Answer:

1s2 2s2 2p3

Explanation:

we know that the number of electrons in an atom is equal to number of protons. So the number of electrons here is 7.

Using Moller chart, the electronic configuration is writen by the electrons first enterring into 1s then into 2s after 2p. The s orbital accomodates maximum of 2 electrons.

∴ for atomic no. 7 nitrogen atom, electronic configuration is 1s2 2s2 2p3.

5 0
3 years ago
Read 2 more answers
A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what
Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

1/[a]_{t} = kt +1/[a]

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

1/[a]t = 49 M-1

[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
3 years ago
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