Answer:
the alkaline earths possess many of the characteristics properties of metals.Alkaline earths have low electron affinities and low electronegativities. As with the alkali metals, the properties depend on the ease with which electrons are lost. The alkaline earths have two electrons in the outer shell. They have smaller atomic radii than the alkali metals. The two valence electrons are not tightly bound to the nucleus, so the alkaline earths readily lose the electron to form divalent cations.
The molar mass of the product is equal to 62g/mol.
<h3>Mole calculation</h3>
To calculate the molar mass of a compound it is necessary to have knowledge of the atomic mass of all the elements involved.
In the case of the question, we have the reaction between flourine and magnesium, which represents the element of group 2 with the presented electronic configuration.
Thus, we have the following reaction:

So, just add the molar masses, having:


So, the molar mass of the product, round to the nearest tenth, is equal to 62g/mol.
Learn more about mole calculation in: brainly.com/question/2845237
Answer:
See image attached
Explanation:
a)
The full reaction mechanism of step 1 was obtained from Bartleby and attached to this answer. The steps involved in the reaction are:
1) Loss of Br- and formation of a carbocation
2) Attack of CH3CN on the carbocation
4) Formation of a quaternary nitrogen intermediate
5) Attack of water on the quaternary nitrogen intermediate
6) Loss of the water molecule
5) Formation of the amide product
b)
i) sodium hydroxide
ii) HCl
What's the difference between A and C because that's the correct answer