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Anna [14]
2 years ago
5

Look at the reaction below. upper h subscript 2 upper s upper o subscript 4 (a q) plus upper c a (upper o upper h) subscript 2 (

a q) right arrow upper c a upper s upper o subscript 4 (a q) plus 2 upper h subscript 2 upper o (l). which substance is the base in the reaction? 2h2o (l) h2so4 (aq) caso4 (aq) ca(oh)2 (aq)
Chemistry
2 answers:
kogti [31]2 years ago
8 0

In the given reaction, the substance that is the base of the reaction is CaSO_4. The correct option is C.

<h3>What is a base?</h3>

The base is a slippery liquid that is bitter and turns red litmus paper to blue.

Bases react with acids to form salts.

Then bases have pH above 7.

Examples of bases are calcium carbonate, sodium hydroxide, etc.

Thus, the correct option is C.

Learn more about bases

brainly.com/question/485375

AlexFokin [52]2 years ago
8 0

Answer:

D. Ca(OH)2 (aq)

Explanation:

Correct on Edge 2022!!!

Good luck everyone, you got this! Have a great day!

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What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2
malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O

The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

                 100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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5 reasons to be grateful of your teachers for is

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