Answer:
B.
Explanation:
There are the same amount of black circles in the reactant and product. There are also the same amount of white circles in the product and reactant.
Answer:
The elements on the left-side of the periodic table are relatively electron deficient. So due to their comparatively low effective nuclear charges (the net positive charge of the protons minus the shielding core electrons below the valence level), their electrostatic hold on these electrons are weak.
Elements further right on the period table though, have higher effective nuclear charges and stabilize electrons more effectively. Which leads to localized covalent bonding and the formation of molecules.
The right side contains non metals while the left side contains metals.
Metals lose electrons (negative electrons). They now have more protons, therefore making the ion positive.
Non metals gain electrons (positive electrons). So the ion has more electrons than protons which makes the ion negative.
Answer:
<u>∆H° reaction = -890.3 kJ</u>
Explanation:
The given equation is :

Now ,
O2 is in the standard state so its ∆H° is zero.
∆H° is calculated by considering the formation of CO2 , H2O and CH4 .
..........∆H°a = -393.5 kJ
.....∆H°b = -285.8 kJ
..........∆H°c = -74.8 kJ
Multiply equation of water H2O by 2
and reverse the direction of equation of CH4
Hence the sign of ∆H°c = +74.8 kJ becomes +ve.
We are doing this because CH4 is to be in the reactant side not in the product side.
∆H° reaction = ∆H°a +2(∆H°b) -∆H°c
∆H° reaction = -393.5 - 2(285.8) + 74.8
∆H° reaction = -890.3 kJ
The correct answer would be A. The symbol Eo would represent the cell potential of an electrolytic cell. This potential is being created by two metals that possess different properties. The energy per charge that is available from the reaction of the metals is the measure of this potential and is related to the equilibrium constant, K.