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Anna [14]
3 years ago
5

Look at the reaction below. upper h subscript 2 upper s upper o subscript 4 (a q) plus upper c a (upper o upper h) subscript 2 (

a q) right arrow upper c a upper s upper o subscript 4 (a q) plus 2 upper h subscript 2 upper o (l). which substance is the base in the reaction? 2h2o (l) h2so4 (aq) caso4 (aq) ca(oh)2 (aq)
Chemistry
2 answers:
kogti [31]3 years ago
8 0

In the given reaction, the substance that is the base of the reaction is CaSO_4. The correct option is C.

<h3>What is a base?</h3>

The base is a slippery liquid that is bitter and turns red litmus paper to blue.

Bases react with acids to form salts.

Then bases have pH above 7.

Examples of bases are calcium carbonate, sodium hydroxide, etc.

Thus, the correct option is C.

Learn more about bases

brainly.com/question/485375

AlexFokin [52]3 years ago
8 0

Answer:

D. Ca(OH)2 (aq)

Explanation:

Correct on Edge 2022!!!

Good luck everyone, you got this! Have a great day!

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A chemist dissolves 398. Mg of pure hydrochloric acid in enough water to make up 210. ML of solution. Calculate the pH of the so
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Answer:

THE pH OF THE SOLUTION IS 1.28

Explanation:

Step 1: Calculate the mass concentration of HCl

398 mg in 210 mL

1 L = 10^3 mL

1 g = 10^3 mg

398 *10^-3 g in 210 *10^-3 L

398 *10^-3 in 0.210 L

mass concentration = (0.398 * 1/ 0.210) g/dm3

= 1.895 g/dm3

Step 2: calculate the molar concentration

Molar mass of HCl = ( 1 + 35.5) = 36.5 g/mol

Molar concentration = mass concentration / RMM

Molar conc. = 1.895 / 36.5

Molar conc. = 0.0519 mol/dm3

So therefore, the molar concentartion of the solution is equal to the concentration of HCl.

In other words, [HCl] = 0.0519 mol/dm3

This shows that at 1 L of this solution contains 0.0519 moles of HCl

Step 3: write the dissiociation equation of HCl in water

HCl(aq) + H2O(l) --------> H30^+ (aq) + Cl- (aq)

Since HCl is a strong acid, it will dissociate completely in water forming the above products.

So we can say that:

[H3O+] = [HCl] = 0.0519 moles/ dm3

Step 4: calculate the pH

pH = -log[H3O+]

pH = -log (0.0519)

pH = 1.28(3 significant decimal place)

The pH of the solution is 1.28

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