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dusya [7]
3 years ago
8

Describe four effects that radiation can have on the human body.

Chemistry
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

There are many effects of radiation to the human body. (if you watch the 100, you'll see what happens)

Exposure to very high levels of radiation, such as being close to an atomic blast, can cause acute health effects such as

1. weakness

a/ fatigue,

b/ fainting,

c/ confusion.

2.Bleeding from the nose,

a/ mouth,

b/ gums,

c/ rectum

3. Bruising,

a/ skin burns,

b/ open sores on the skin,

c/ sloughing of skin.

4. Dehydration.

5. Diarrhea, bloody stool.

6. Fever.

7. Hair loss.

8. Inflammation of ex

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Answer:

See explanation

Explanation:

A <u>trans</u> alkene is more stable than a <u>cis alkene</u> because they have fewer steric interactions.

<em>⇒ In a cis alkene there is steric hindrance, because the methyl groups are on the same side of the double bond. </em>

<em>Because of this steric crowding, there are van der Waals repulsive forces between the electron clouds of the groups. </em>

<em> </em>

<em>This decreases the stability of the cis alkene.</em>

<em />

In an elimination reaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called <u>anti</u> periplanar.

<em> ⇒ 'Anti’ refers to the two functional groups lying on opposite sides of the plane of the bond</em>

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<em> ⇒ The SN1 reaction is a substitution reaction, and means "nucleophilic substitution".The "1" says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile.</em>

while in an <u>E1</u><u> </u>mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond.

<em> ⇒ E1 indicates a elimination, unimolecular reaction</em>

<em>This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species.</em>

<em>.This is a classic elimination reaction – forming a new C–C(π) bond, and breaking a C–H and C–leaving group bond.</em>

CH3CH2Br and NaOH react by an <u>SN2</u><u> </u>mechanism.

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Stronger bases, like hydroxide, favor<u> E2</u> reactions, whereas weaker bases, like water favor, <u>E1</u> reactions

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<u>Elimination reactions</u> are regioselective, favoring formation of the more substituted and more stable alkene.

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