Mole ratios
Reactants and products
Type of reaction eg equilibrium
Enthalpy
Charges of ions
Answer:
<u>89.6 L</u>
Explanation:
In normal conditions,
<u><em>For every </em></u><u><em>1 mole</em></u><u><em> of carbon dioxide at STP, it occupies </em></u><u><em>22.4 L</em></u><u><em> of volume.</em></u>
<u><em /></u>
============================================================
Solving :
⇒ 1 mole : 22.4 L
⇒ 1 × 4 : 22.4 × 4
⇒ 4 moles : <u>89.6 L</u>
- increasing the concentration of N₂
- increasing the concentration of O₂
- decreasing the concentration of NO
- increasing the temperature
:)
63ldldldkddldlmdndnj djd dr djd did d ddnjddd