2 years ago

A piece of copper has a volume of 100.0 cm³. If the mass is 890 g, what is the density of copper

Physics

1 answer:

Hoochie [10]2 years ago

3 0

Answer:

Explanation:

mass = m =890 g volume = v =100cm³

Density = m/v =890g / 100cm³ =8.9g/cm³

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Read 2 more answers

Determine the magnitude of the electric field at the point P. Express your answer in terms of Q, x, a, and k. Express your answe

Sav [38]

Complete Question

The question image is in the first uploaded image

Answer:

$E=\frac{KQ*4xa}{(x^2-a^2)^2}$

Explanation:

From the question we are told that

Distance b/w Q mid point and P is given as x

Generally the equation for magnitude of the electric field at the point P is given as

$E=\frac{kQ}{d^2}$

where

$k=\frac{1}{4\pi e_0}$

$d=x^2-a^2$

Therefore

$E= \frac{1}{4\pi e_0} \frac{Q}{(x^2-a^2)^2}- \frac{1}{4\pi e_0} \frac{Q}{(x^2+a^2)^2}$

$E= \frac{Q}{4\pi e_0} (\frac{1}{(x^2-a^2)^2}- \frac{1}{(x^2+a^2)^2})$

Therefore equation for magnitude of the electric field at the point P is

$E=\frac{KQ*4xa}{(x^2-a^2)^2}$

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