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Alecsey [184]
1 year ago
13

A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i

n 10 s. Find (a) the total work done on the car
Physics
1 answer:
attashe74 [19]1 year ago
4 0

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
  • As per Newton's equation of motion, V= U+at
  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
  • So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

#SPJ1

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3 years ago
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon
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Answer:

241.8 N.

Explanation:

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Centripetal force = mv^2/r

F = mg + mv²/r

F = m(g + v²/r)

where,

m = mass

= 9 kg

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3 0
2 years ago
A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini
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Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, m_1=4\ kg

Mass of dove, m_2=1\ kg

Initial velocity of falcon, u_1=3\ m/s

Initial velocity of dove, u_2=2\ m/s

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V is the velocity after impact

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

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V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

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The speed as witch it is moving
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