Answer:
the shooting angle ia 18.4º
Explanation:
For resolution of this exercise we use projectile launch expressions, let's see the scope
R = Vo² sin (2θ) / g
sin 2θ = g R / Vo²
sin 2θ = 9.8 75/35²
2θ = sin⁻¹ (0.6)
θ = 18.4º
To know how for the arrow the tree branch we calculate the height of the arrow at this point
X2 = 75/2 = 37.5 m
We calculate the time to reach this point since the speed is constant on the X axis
X = Vox t
t2 = X2 / Vox = X2 / (Vo cosθ)
t2 = 37.5 / (35 cos 18.4)
t2 = 1.13 s
With this time we calculate the height at this point
Y = Voy t - ½ g t²
Y = 35 sin 18.4 1.13 - ½ 9.8 1,13²
Y = 6.23 m
With the height of the branch is 3.5 m and the arrow passes to 6.23, it passes over the branch
Answer:
1. Revolve around a point
2. Formed from dust and gas particles
3. Exoplanets and associated star orbit a common center of mass
4. Composed of gases found in Jupiter and Saturn
You know I’m going to be honest I don’t feel like it
Airplanes produce lift from the air moving over their wings. Stall speed is a metric that refers to the minimum speed required for an airplane to produce lift. When airplanes fly slower than their respective stall speed, they won't produce lift. ... If an airplane's speed drops below its stall speed, it won't produce lift.
