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Marrrta [24]
3 years ago
13

Now suppose the crate is lifted so rapidly that air resistance was significant during the raising. How much work was done by the

lifting force as the box was raised 1.5 m?
Physics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

A

Explanation:

- The complete question is:

" A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is  supported by an upward force of 100 N).Now suppose the crate is lifted so rapidly that air resistance was significant during the raising. How much work was done by the lifting force as the box was raised 1.5 m?"

Options:

1. More than 150 J

2. A bit less than 150 J because the air partially supported the crate.

3. No work was done.

4. Still 150 J

5. None of these

Solution:

- As the box is raised the work is done against gravity and air resistance opposes the motion of box. Hence, both the force of gravity ( Weight and air resistance act downward).

- The amount of work done is the sum of both work done against gravity and against air resistance.

-                         W = W_g + W_r

                         W > W_g

                         W > 100*1.5

                         W > 150 J

- Hence, the work done is greater than 150 J i.e work is also done against ai r resistance.  

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Substituting the values,

                             V^{2} = 0^{2} + 2(-9.8 m/s^{2})(-1.25 m)

                             V^{2} = 24.5 m/s

                             V = \sqrt{24.5} \ m/s

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                            V = ± 4.95 m/s

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Since the ball is moving downward, the final velocity of the ball when it hits the floor is  V = - 4.95 m/s  

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assume the mass of the ball still remain, m = 0.120 kg

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the final velocity, v = 0 m/s  

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                            0^{2} = U^{2} + 2(-9.8 m/s^{2})(0.820 m)

                            0 = U^{2} - 16.072 m/s

                            U^{2} = 16.072 m/s

                            U = \sqrt{16.072} \ m/s

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From Newton's second law of motion, applied force is directly proportional to the rate of change in momentum.

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       ⇒      Impulse = Change in momentum

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                      Impulse  = 1.0752 kgm/s

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