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kolbaska11 [484]
3 years ago
8

Compare and contrast microscopic and macroscopic energy transfer Give least three comparisons for each

Physics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

Differences

microscopic refers to substances visible to the naked eye

macroscopic are substances invisible to naked eye

Similarities

both refer to different scales that are useful to determining the size to different compounds.

Explanation:

Ima find more

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If it takes 100 N to get a 10 kg object to accelerate at 10m/s/s, how much force will it take to get a 20 kg object to accelerat
yan [13]

Answer: C) 200 N

Explanation:

The force F is defined as:

F=m.a

Where:

m=20 kg is the mass of the object

a=10 m/s^{2} is the acceleration

Then:

F=(20 kg)(10 m/s^{2})

Finally:

F=200 N

Hence, the correct option is C.

7 0
3 years ago
A piano has a mass of 99 kg. What is the weight of the piano?
Blababa [14]

Explanation:

weight of the piano = mg

w = 99 x 10 =990 N

7 0
3 years ago
A conical container of radius 6 ft and height 24 ft is filled to a height of 19 ft of a liquid weighing 64.4 lb divided by ft cu
kobusy [5.1K]

Answer:

Part (i) work required to pump the contents to the​ rim is 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5ft above the​ cone's rim is 426,484.878 lb.ft

Explanation:

The center of mass of a uniform solid right circular cone of height h lies on the axis of symmetry at a distance of h/4 from the base and 3h/4 from the top.

Center mass of the liquid Z = (24-19)ft + 19/4 = 5ft + 4.75ft = 9.75 ft

Mass of liquid in the cone = volume × density (ρ) =  ¹/₃.π.r².h.ρ

where;

r is the radius of the liquid surface = [6*(19/24)]ft = 4.75ft

ρ is the density of liquid = 64.4 lb/ft³

h is the height of the liquid = 19 ft

Mass of liquid in the cone = ¹/₃ × π × (4.75)² × 19 × 64.4 = 28,914.229 lbs

Part (i)  work required to pump the contents to the​ rim

Work required = 28,914.229 lbs × 9.75 ft = 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5 ft above the​ cone's rim

Extra work required = 28,914.229 lb ×  5ft = 144571.145 lb.ft

Total work required = (281,913.733 +  144571.145) lb.ft

                                 = 426,484.878 lb.ft

5 0
3 years ago
Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when i
LenaWriter [7]

The given question is incomplete. The complete question is as follows.

You throw a ball vertically upward, and as it leaves your hand, its speed is 26.0 m/s.

(a) How high (in m) does it rise above the level where it leaves your hand?

(b) How long (in s) does it take to reach its highest point?

(c) How long (in s) does the ball take to return to the level where it left your hand after it reaches its highest point?

(d) Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when it returns to the level where it left your hand? (Indicate the direction with the sign of your answer.)

Explanation:

(a) For maximum height, the formula will be as follows.

           v^{2} = u^{2} + 2as

                 a = v^{2} - 2gh

or,                 h = \frac{v^{2}}{2g}

                        = \frac{(26)^{2}}{2 \times 9.8}

                        = \frac{676}{19.6}

                        = 34.5 m/s

Hence, it rises 34.5 m/s above the level where it leaves your hand.

(b) Time to reach maximum height is as follows.

            v = u + at

or,           v - gt = 0

                 t = \frac{v}{g}

                   = \frac{26}{10}

                   = 2.6 sec

Therefore, it will take 2.6 sec to reach its highest point.

(c)  Time taken by the ball to ascent is equal to the time it has taken to descent.

Therefore, time taken by the ball to return to the level where it left your hand after it reaches its highest point? is also 2.6 sec.

(d)  Speed of the ball will be 26 m/s in the downward direction. Hence, the velocity will be -26 m/s.

3 0
3 years ago
If a metal ball of mass 45kg is released at a height of 50m with acceleration due to gravity of 1.66m/s^2 then how much time wil
Yuki888 [10]

Answer:

t = 7.76sec

Explanation:

t²=(2s)/a

t²=(2 x 50)/1.66

t²=60.24

t=√60.24

t=7.76sec

3 0
3 years ago
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