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mestny [16]
3 years ago
13

Which of the following is not a result when a change to an equilibrium system is applied? (2 points)

Chemistry
2 answers:
Ray Of Light [21]3 years ago
8 0
It should be increasing the rate of the forward reaction will cause a shift to the left because the external stress, which is the increase in rate, will cause the reaction to be unbalanced, and to reach equilibrium it needs to shift to the right.
Ksju [112]3 years ago
6 0

Answer: Option (2) is the correct answer.

Explanation:

According to LeChatelier principle, any change in the equilibrium of a chemical reaction will result in shifting of equilibrium which is opposing the change.

Therefore, when we increase the rate of the reverse reaction that is, we move towards left side then this will actually cause a shift to the right hand side which is opposing the change.

Thus, we can conclude that increasing the rate of the reverse reaction will cause a shift to the left is not a result when a change to an equilibrium system is applied.

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What reaction is C+O2=CO2
slamgirl [31]

Answer:

Combination or synthesis

Explanation:

The reaction given below:

             C    +  O₂    →  CO₂  

The reaction above is termed a synthesis or combination reaction because two substances are combining to give a product.

  • A synthesis reaction involves the formation of a single product from two or more reactants.
  • The driving force for such reaction is the large and negative heat of formation of the product.
5 0
2 years ago
Which can occur in a physical change?<br> The mass can increase
solong [7]
In a physical change the form changes or the state of the matter. For instance water can freeze and water can melt, but it is still water.

Please vote my answer brainliest! Thanks.
3 0
3 years ago
A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?
Komok [63]

Answer:

Ok:

Explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.

7 0
2 years ago
1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

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