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kompoz [17]
3 years ago
9

Ok so the answer for this question, A student measured the mass of salt that can dissolve in 100 mL of water at five different t

emperatures. Which variable should go in the X axis? The answer is B, the temperature of water. I do school on k12, so if you are too this is the correct answer for you! And since this quiz was pretty hard and confusing for many of us I am going to put all the answers for this quiz! For me this quiz is called 1.11 quiz: Analyze Results.
Question 1- A student measured the maximum mass of salt that can dissolve in 100 mL of water at five different temperatures. Which variable should go in the x-axis?
-The temperature of water

Question 2-Which type of graph would best show the the data collected from measuring time for a ball to fall from varying heights?
-A scatter plot

Question 3- A student measured the flow time of 10 g of honey at different temperatures and graphed the data.
-The temperature is the independent variable.

Question 4- What is the relationship between the variables on this graph?
- As the temperature increases, the flow time increases.

Question 5- What is missing from this graph? (Not an answer put the graph is called number of sunspots each year)
-Axis Label

I hope this helped everyone out! Feel free to ask me anything in the comments, I will try to answer them as fast a I can! (Also to add in here is that I'm in k12 so if these answers aren't correct then that would be why!)
Chemistry
1 answer:
Dmitriy789 [7]3 years ago
8 0

Answer:

penguin

Explanation:

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[50 Points] In the experiment below, Beaker 1 contains 12.0 M HCl. Each subsequent beaker is diluted by 50%. What is the [OH-] i
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Answer:

2.67x10⁻¹⁴M = [OH-]

Explanation:

To solve this question we need first to find the HCl concentration of the beaker 6. Then, using:

Kw = [OH-][H+]

<em>Where Kw = 1x10⁻¹⁴</em>

<em>[OH-] is our incognite</em>

<em>[H+] is = [HCl]</em>

<em />

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Beaker 3 = 6.0M / 2 = 3.0M

Beaker 4 = 3.0M / 2 = 1.5M

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Beaker 6 = 0.75M / 2 = 0.375M

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1x10⁻¹⁴ / [H+] = [OH-]

1x10⁻¹⁴ / 0.375M = 2.67x10⁻¹⁴M

<h3>2.67x10⁻¹⁴M = [OH-]</h3>
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