Well a molecule of water is equal to 1 Oxygen and 2 Hydrogen each, so it'd be 2 molecules of water
In the Proton category: symbol p, and +1 charge
In the Neutron category: symbol n, 0 charge
In the Electron category: symbol e, -1 charge
I’m gonna be honest I’m just answering So I could upload my question
Answer:
2.67x10⁻¹⁴M = [OH-]
Explanation:
To solve this question we need first to find the HCl concentration of the beaker 6. Then, using:
Kw = [OH-][H+]
<em>Where Kw = 1x10⁻¹⁴</em>
<em>[OH-] is our incognite</em>
<em>[H+] is = [HCl]</em>
<em />
Beaker 2 = 12.0M / 2 = 6.0M
Beaker 3 = 6.0M / 2 = 3.0M
Beaker 4 = 3.0M / 2 = 1.5M
Beaker 5 = 1.5M / 2 = 0.75M
Beaker 6 = 0.75M / 2 = 0.375M
HCl = 0.375M = [H+]
1x10⁻¹⁴ / [H+] = [OH-]
1x10⁻¹⁴ / 0.375M = 2.67x10⁻¹⁴M
<h3>2.67x10⁻¹⁴M = [OH-]</h3>
4, 5, 4, 6 is how to balance the equation