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nikdorinn [45]
2 years ago
11

If an object has an initial velocity of 2.0 m/s and its rate of change in velocity is 3.0 m/s2

Physics
1 answer:
erica [24]2 years ago
6 0

Answer:

14m/s2

Explanation:

initial velocity=2m/s

final velocity =?

time=4s

acceleration=3.0m/s

v=u+at

v=(2)+(3*4)

v=14m/s

by substituting the values in the equation we get the value 14m/s.

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How much force is needed to accelerate a 1,800kg car at rate of 1.5 m/s2?
topjm [15]

<u>Given data:</u>

acceleration (a) = 1.5 m/s² ,

           mass (m) = 1800 Kg ,

        Determine F = ?

         <em>From Newtons II law</em>

                          F = m.a   N

                              = 1800× 1.5

                             = 2700 N

<em>2700 N force needed to accelerate the car</em>

7 0
3 years ago
What are the orders of the lunar cycle?
skad [1K]
The 8 moon phases in order are New moon, Waxing Crescent, First Quarter, Waxing Gibbous, Full moon, Waning Gibbous, Third Quarter, and finally Waxing Crescent.
8 0
3 years ago
If a ball is thrown up at an initial speed of 40. m/s, how many seconds does it take to reach the top of its path?
natka813 [3]

Answer:

Time, t = 4.08 secs

Explanation:

<u>Given the following data;</u>

Initial velocity, U = 40m/s

To find the time, we would use the first equation of motion;

V = U + at

Where;

  • V is the final velocity.
  • U is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

<em>Making time, t the subject of formula, we have;</em>

t = \frac{V - U}{a}

We know that acceleration due to gravity, g is 9.8m/s².

a = g = - 9.8m/s² because the ball is thrown in the opposite direction.  

Also, the final velocity is equal to zero (0) because the ball reached its maximum height.

<em>Substituting into the equation, we have;</em>

t = \frac{0 - 40}{-9.8}

t = \frac{-40}{-9.8}

Time, t = 4.08 secs

<em>Therefore, it will take the ball 4.08 seconds to reach the top. </em>

5 0
3 years ago
Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s
nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

         v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

         v = 0 + at

let's calculate

         v = 8  5

         v = 40 m / s

8 0
2 years ago
A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol
ELEN [110]

Answer:

v = 719.2 m / s and     a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

           v - v₀ = v_{e} ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

            m_fuel = 75 10

            m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

              M = 3000 -750 = 2250 kg

let's calculate

            v - 0 = 2500 ln (3000/2250)

            v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

             Push = v_{e} dM / dt

let's calculate

             Push = 2500  75

             Push = 187500 N

            If we use Newton's second law

             F = m a

             a = F / m

let's calculate

              a = 187500/2250

              a = 83.33 m / s²

7 0
3 years ago
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