If an object has an initial velocity of 2.0 m/s and its rate of change in velocity is 3.0 m/s2
1 answer:
You might be interested in
Answer:
Time, t = 4.08 secs
Explanation:
<u>Given the following data;</u>
Initial velocity, U = 40m/s
To find the time, we would use the first equation of motion;
Where;
- V is the final velocity.
- U is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
<em>Making time, t the subject of formula, we have;</em>
We know that acceleration due to gravity, g is 9.8m/s².
a = g = - 9.8m/s² because the ball is thrown in the opposite direction.
Also, the final velocity is equal to zero (0) because the ball reached its maximum height.
<em>Substituting into the equation, we have;</em>
Time, t = 4.08 secs
<em>Therefore, it will take the ball 4.08 seconds to reach the top. </em>
Answer:
v = 719.2 m / s and a = 83.33 m / s²
Explanation:
This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is
v - v₀ = ln (M₀ / M)
where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket
In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s
m_fuel = 75 10
m_fuel = 750 kg
As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is
M = 3000 -750 = 2250 kg
let's calculate
v - 0 = 2500 ln (3000/2250)
v = 719.2 m / s
To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is
Push = v_{e} dM / dt
let's calculate
Push = 2500 75
Push = 187500 N
If we use Newton's second law
F = m a
a = F / m
let's calculate
a = 187500/2250
a = 83.33 m / s²