Complete Question
The complete question shown on the first uploaded image
Answer:
a)
The force on Q due to dipole is Attractive
b)
The charge Q exerts attractive force on the dipole
c)
Yes from the above parts, force depends on the sign of charge
d)
![F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]](https://tex.z-dn.net/?f=F%20%3D%20kQq%5B%5Cfrac%7Bd%5E%7B2%7D%2B2rd%7D%7Br%5E%7B2%7D%28d%2Br%29%5E%7B2%7D%7D%20%5D)
e)
The magnitude o force decrease by a factor of 8.0 times
Explanation:
The explanation is shown on the second uploaded image
Answer:
voltmeter
Explanation:
A voltmeter is the instrument used to measure a potential difference between two points in an electric circuit.
Answer:
1.045 m from 120 kg
Explanation:
m1 = 120 kg
m2 = 420 kg
m = 51 kg
d = 3 m
Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.
By use of the gravitational force
Force on m due to m1 is equal to the force on m due to m2.



3 - y = 1.87 y
3 = 2.87 y
y = 1.045 m
Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.
An airplane is flying at a constant speed in a positive direction. It slows down when it approaches the airport where it's going to land. this is an example of negative acceleration (D).